每日leetcode--(17) Letter Combinations of a Phone Number
遞迴思想,字串逐步減短
#include <iostream> #include <vector> #include <algorithm> #include <math.h> #include <stdio.h> #include <string> using namespace std; string A[10] = {"","","abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"}; class Solution { public: vector<string> letterCombinations(string digits) { vector<string> res; return helper(res,digits); } vector<string> helper(vector<string> V, string s) { if(s=="") { return V; } else { vector<string> ret; int num = s[0] - '0'; string s1 = A[num]; if(V.size()==0) { for(int i = 0;i<s1.size();i++) { string s = ""; s.append(1,s1[i]); ret.push_back(s); } } else { for(int i = 0;i<V.size();i++) { for(int j = 0;j<s1.size();j++) { string t_s = V[i]; t_s.append(1,s1[j]); ret.push_back(t_s); } } } return helper(ret, s.substr(1,s.size()-1)); } } };
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