Product of Array Except Self 陣列除自身的所有乘積
Given an array of n integers where n > 1, nums,
return an array output such that output[i] is
equal to the product of all the elements of nums except nums[i].
Solve it without division and in O(n).
For example, given [1,2,3,4], return [24,12,8,6].
Follow up:
Could you solve it with constant space complexity? (Note: The output array does not
class Solution { public: //基本思想是兩個陣列left，right，分別儲存從左到右 從右到左的乘積，然後對應位置相乘即可 //為了優化空間 左邊的陣列可以用一個變數代替 右邊的陣列可以複用結果陣列 vector<int> productExceptSelf(vector<int>& nums) { int len=nums.size(); vector<int> res(len,0); if(len<2) return res; int i; res[len-1]=1;//右邊的乘積 for(i=len-1;i>0;i--) res[i-1]=res[i]*nums[i]; int left=1;//左邊的乘積 for(i=0;i<len;i++) { res[i]*=left; left=left*nums[i]; } return res; } };
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