【題解】Binary Tree Right Side View
這道leetcode最新出的題,貌似也不是很難,用廣度優先搜尋即可,參考程式碼如下。
class Solution { public: vector<int> rightSideView(TreeNode *root) { vector<int> answer; queue<TreeNode *> queue, temp_queue; TreeNode * front = 0; if (NULL == root) { return answer; } queue.push(root); answer.push_back(root->val); while (!queue.empty()) { while (!temp_queue.empty()) { temp_queue.pop(); } while (!queue.empty()) { front = queue.front(); if (NULL != front->left) { temp_queue.push(front->left); } if (NULL != front->right) { temp_queue.push(front->right); } queue.pop(); } queue = temp_queue; if (!queue.empty()) { answer.push_back(queue.back()->val); } } return answer; } };
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