靜態連結串列的建立：

#include <stdio.h>
struct student
{
	int number;
	float score;
	struct student *next;
};                                 //結點的定義
int main()
{
	struct student *head,*p,a,b,c;
	a.number=1234,a.score=90.5;
	b.number=1235,b.score=80.9;
	c.number=1238,c.score=97.6;
	head=&a,a.next=&b,b.next=&c,c.next=NULL,p=head;
	do                                         //輸出此靜態連結串列
	{	printf("%ld,%6.2f\n",p->number,p->score);
    p=p->next;}
    while(head!=NULL);
	return 0;
}
 

單向動態連結串列：

#include <stdio.h>
#include <stdlib.h>
#define LEN sizeof(struct student)

    struct student
    {
        int num;
        float score;
        struct student *next;
    };
                                     //節點的定義
    struct student* creat(void)     //編寫建立動態連結串列的函式
    {
        struct student *p1,*p2,*head;
        p1=p2=(struct student*)malloc(LEN);
        scanf("%d %f",&p1->num,&p1->score);
        head=p1;
        while(p1->num)
        {
            p2->next=p1;     //A  line
            p2=p1;           //B  line
            p1=(struct student*)malloc(LEN);
            scanf("%d %f",&p1->num,&p1->score);         
        }
        p2->next=NULL;
        return (head);                        //返回值為建立的動態連結串列的頭指標
    }


int main()
{
    struct student *pt,*p;
    pt=creat();
    p=pt;
    if(p!=NULL)
    do                                        //輸出動態連結串列
    {
       printf("%d %5.1f\n",p->num,p->score);
        p=p->next;
    }while(p!=NULL);
    return 0;
}
 

構建好了後，再輸出連結串列就行了，方法和靜態連結串列的輸出方法一樣。