我們先看看XML檔案究竟長啥樣 :)

<?xml version="1.0" encoding="utf-8" ?> <shop> <province provinceName="安徽省"> <city cityName="合肥市"> <area areaName="廬陽區"> <LNshop shopName="A" address="A地址"/> <LNshop shopName="B" address="B地址"/> <LNshop shopName="C" address="C地址"/> </area> </city> <city cityName="淮北市"> <area areaName="相山區"> <LNshop shopName="D" address="D地址"/> </area> </city> </province> </shop>

方法一（應該是最為我們熟悉的方法）：

XmlDocument xmlDoc = new XmlDocument(); xmlDoc.Load(@"D:/XMLFile1.xml"); List<Hashtable> list = new List<Hashtable>(); XmlNodeList nodeList = xmlDoc.SelectSingleNode("shop").ChildNodes; //獲取根節點的所有子節點 foreach (XmlNode provinceList in nodeList) //遍歷所有province節點 { foreach (XmlNode cityList in provinceList) //遍歷所有city節點 { foreach (XmlNode areaList in cityList) //遍歷所有area節點 { foreach (XmlNode shopList in areaList) //遍歷所有LNshop節點 { Hashtable ht = new Hashtable(); ht.Add("provinceName", provinceList.Attributes["provinceName"].Value); ht.Add("cityName", cityList.Attributes["cityName"].Value); ht.Add("areaName", areaList.Attributes["areaName"].Value); ht.Add("shopName", shopList.Attributes["shopName"].Value); ht.Add("address", shopList.Attributes["address"].Value); list.Add(ht); } } } } foreach (Hashtable data in list) { Console.WriteLine("{0}, {1}, {2}, {3}, {4}", data["provinceName"], data["cityName"], data["areaName"], data["shopName"], data["address"]); }

方法二：

XmlDocument xmlDoc = new XmlDocument(); xmlDoc.Load(@"D:/XMLFile1.xml"); List<Hashtable> list = new List<Hashtable>(); XmlNodeList nodes = xmlDoc.SelectNodes("//LNshop"); //獲取LNshop節點 foreach (XmlNode node in nodes) { Hashtable ht = new Hashtable(); ht.Add("provinceName", node.SelectSingleNode("ancestor::province").Attributes["provinceName"].Value); ht.Add("cityName", node.SelectSingleNode("ancestor::city").Attributes["cityName"].Value); ht.Add("areaName", node.SelectSingleNode("ancestor::area").Attributes["areaName"].Value); ht.Add("shopName", node.Attributes["shopName"].Value); ht.Add("address", node.Attributes["address"].Value); list.Add(ht); } foreach (Hashtable data in list) { Console.WriteLine("{0}, {1}, {2}, {3}, {4}", data["provinceName"], data["cityName"], data["areaName"], data["shopName"], data["address"]); }

下面隆重推出方法三（LinqToXML C#版）

// 載入指定的xml檔案 XDocument xml = XDocument.Load(@"D:/XMLFile1.xml"); var list = from node in xml.Descendants("LNshop") //獲取LNshop節點 select new { /* Ancestors 獲取上級元素的集合 * 欲獲取上級元素的屬性無法直接用Attribute獲取， * 只能通過Attributes（沒錯，就多了個s）獲取，且通過Single()方法獲取其屬性值 */ provinceName = node.Ancestors("province").Attributes("provinceName").Single().Value, cityName = node.Ancestors("city").Attributes("cityName").Single().Value, areaName = node.Ancestors("area").Attributes("areaName").Single().Value, shopName = node.Attribute("shopName").Value, shopAddress = node.Attribute("address").Value }; foreach (var data in list) { Console.WriteLine("{0}, {1}, {2}, {3}, {4}", data.provinceName, data.cityName, data.areaName, data.shopName, data.shopAddress); }  

我們不妨看看LinqToXML VB版

Dim xmlDoc As XDocument = XDocument.Load("D:/XMLFile1.xml") Dim List = From el In xmlDoc.<shop>.<province>.<city>.<area>.Elements _ Select el.Ancestors("province").@provinceName, _ el.Ancestors("city").@cityName, _ el.Ancestors("area").@areaName, _ el.@shopName, _ el.@address For Each s In List Console.WriteLine("{0}, {1}, {2}, {3}, {4}", s.provinceName, s.cityName, s.areaName, s.shopName, s.address) Next

VB版看起來更簡潔，贊~/(≧▽≦)/~

謝謝xiaoniaodewen的帖子，也同時感謝fangxinggood與我們分享TA的好方法 :)