Can you solve this equation?

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 235    Accepted Submission(s): 105

Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky. Input The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10); Output For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100. Sample Input 2 100 -4 Sample Output 1.6152 No solution!#include <iostream> using namespace std; double POW(double x,int n) { int i; double sum=1.0; for(i=1;i<=n;i++) sum*=x; return sum; } double find(double x) { return 8*POW(x,4)+7*POW(x,3)+2*POW(x,2)+3*x+6; } int main() { int t; double y,f,l,mid; scanf("%d",&t); while(t--) { scanf("%lf",&y); if(find(0)<=y && find(100)>=y) { f=0; l=100; while(l-f>1e-6) { mid=(f+l)/2; if(find(mid)>y) l=mid; else f=mid; } printf("%.4lf/n",(f+l)/2); } else printf("No solution!/n"); } return 0; }