POJ 2492 A Bug's Life (bug們被悲劇了)
Professor Hopper is researching the sexual behavior of a rare species of bugs. He assumes that they feature two different genders and that they only interact with bugs of the opposite gender. In his exp eriment, individual bugs and their interactions were easy to identify, because numbers were printed on their backs.
Problem
Given a list of bug interactions, decide whether the experiment supports his assumption of two genders with no homosexual bugs or if it contains some bug interactions that falsify it.
相關推薦
POJ 2492 A Bug's Life (bug們被悲劇了)
Background Professor Hopper is researching the sexual behavior of a rare species of bugs. He assumes that they feature two different genders and that they
poj 2492 a bug's life 簡單種類並查集
ont nbsp root 遞推 spl bsp n) void display 題意大致為找同性戀的蟲子。。。。 這個比食物鏈要簡單些。思路完全一致,利用取余操作實現關系之間的遞推。 個人感覺利用向量,模和投影可能可以實現具有更加復雜關系的並查集。 1 #inclu
POJ 2492 A Bug's Life (並查集)
ont set -1 flat com rom init red least Background Professor Hopper is researching the sexual behavior of a rare species of bugs. He assum
poj 2492 A Bug's Life
void string while math isp pla 關系 tmp clu 帶權並查集模2系,也就是給一些關系 ,這些關系是是否同類。問有多少關系錯的。 #include <cstdio> #include <cstring> #
POJ-2492-A Bug's Life(並查集分類)
Description Background Professor Hopper is researching the sexual behavior of a rare species of bugs. He assumes that they feature two different gend
poj 2492 A Bug's Life【帶權並查集】
就是給一個無向圖判是否有奇環 用帶權並查集來做,邊權1表示連線的兩個節點異性,否則同性,在%2意義下進行加法運算即可,最後判相同的時候也要%2,因為可能有負數 #include<iostream> #include<cstdio> using namespace std; const
POJ 2492 - A Bug's Life (種類並查集)
Background Professor Hopper is researching the sexual behavior of a rare species of bugs. He assumes that they feature two different genders and that
POJ 2492 A Bug's Life (帶權並查集)
A Bug's Life Time Limit: 10000MS Memory Limit: 65536K Total Submissions: 45943  
poj 2492 A Bug's Life(並查集)分組並查集
A Bug's Life Time Limit: 10000MS Memory Limit: 65536K Total Submissions: 29058 Accepted: 9467 Description Background Professor Hop
A Bug‘s life POJ 2492 解題報告 (種類並查集)
這也算是種類並查集的一道經典例題了吧,題意就不多解釋了,先寫一些我對種類並查集的一些理解。 種類並查集比普通的並查集多一個relation陣列,relation[i] 記錄了 i 和 其直接父親節點的關係,這個關係的表示因題目而異,種類並查集的重點和難點就是
POJ-2492 A Bug's Life (種類並查集)
A Bug’s Life Background Professor Hopper is researching th
A Bug's Life POJ
先把我的錯誤程式碼發出來,也是想了解到為什麼這樣會錯,如果有大神恰巧路過可否在評論講解一番: #include <iostream> #include <cstdio> #include <cmath> #include <stri
百練 2492 : A Bug's Life --並查集簡單應用
他說每個測試輸出兩行,其實是三行吧,否則PE. 並查集的簡單應用,類似於”發現它,抓住它”. 描述 Hopper 博士正在研究一種罕見種類的蟲子的性行為。他假定蟲子只表現為兩種性別,並且蟲子只與異
2492 A Bug's Life (帶權並查集)
解題思路:d[i]=0表示父節點同性 d[i]==1 表示與父節點異性 #include<iostream> #include<cstdio> #include<vector> #include<algorithm>
數算實習 A bug's life 並查集
背景 Hopper教授正在研究一種稀有物種的性行為。他假設他們有兩種不同的性別,他們只與異性發生性行為。每個個體的編號都印在他們的背上。 問題 給出一個bug之間的性行為列表,確定實驗是否支援他的假設:該物種之間不存在同性戀關係。 輸入 輸入的第一行包含實驗的數
zcmu 1437 A Bug's Life(並查集)
【題目】 1437: A Bug's Life Time Limit: 1 Sec Memory Limit: 128 MB Submit: 112 Solved: 49 [Submit][Status][Web Board] Description Prof
【ZCMU1437】A Bug's Life(種類並查集)
題目連結 1437: A Bug's Life Time Limit: 1 Sec Memory Limit: 128 MB Submit: 113 Solved: 50 [Submit][Status][Web Board] Description Pr
POJ2492 A Bug's Life
Description Background Professor Hopper is researching the sexual behavior of a rare species of bugs. He assumes that they feature two d
poj 2492A Bug's Life
Description Background Professor Hopper is researching the sexual behavior of a rare species of bugs. He assumes that they feature two d
A Bug's Life(加權並查集)
Description Background Professor Hopper is researching the sexual behavior of a rare species of bugs. He assumes that they feature t