求三角形面積三種方式
阿新 • • 發佈:2019-01-24
#include <math.h>
struct point{double x,y;};
//計算cross product (P1-P0)x(P2-P0)
double xmult(point p1,point p2,point p0){
return (p1.x-p0.x)*(p2.y-p0.y)-(p2.x-p0.x)*(p1.y-p0.y);
}
double xmult(double x1,double y1,double x2,double y2,double x0,double y0){
return (x1-x0)*(y2-y0)-(x2-x0)*(y1-y0);
}
//計算三角形面積,輸入三頂點
double area_triangle(point p1,point p2,point p3){
return fabs(xmult(p1,p2,p3))/2;
}
double area_triangle(double x1,double y1,double x2,double y2,double x3,double y3){
return fabs(xmult(x1,y1,x2,y2,x3,y3))/2;
}
//計算三角形面積,輸入三邊長
double area_triangle(double a,double b,double c){
double s=(a+b+c)/2 ;
return sqrt(s*(s-a)*(s-b)*(s-c));
}
//計算多邊形面積,頂點按順時針或逆時針給出
double area_polygon(int n,point* p){
double s1=0,s2=0;
int i;
for (i=0;i<n;i++)
s1+=p[(i+1)%n].y*p[i].x,s2+=p[(i+1)%n].y*p[(i+2)%n].x;
return fabs(s1-s2)/2;
}