資料結構(線性結構習題)Problem A: 求集合的交併補集
阿新 • • 發佈:2019-01-25
#include <stdio.h> #include <malloc.h> #include <iostream> #include <stdlib.h> #define LIST_INIT_SIZE 100 #define LISTINCREMENT 10 #define OK 1 #define OVERFLOW -1 #define ERROR 0 typedef int Status; typedef int ElemType; typedef struct SqList{ ElemType * elem; //陣列首地址 int listSize; //表容量;當前表的容量 int length; //表長,代表當前陣列中有效元素的個數 }SqList; // 下面實現nitList操作,即初始化一個空的線性表 Status InitList_Sq(SqList &L) { L.elem=(ElemType *)malloc(LIST_INIT_SIZE*sizeof(ElemType)); //malloc的返回值型別是void *; //使用時要及時進行強制型別轉換 if(!L.elem) exit(OVERFLOW); L.listSize=LIST_INIT_SIZE; L.length=0; return OK; } Status CreateList(SqList &La,int na){ for(int i = 1;i<=na;++i){ ElemType e; // printf("請輸入第%d個元素",i); scanf("%d",&e); if(La.length >= La.listSize) { La.elem=(ElemType *)realloc(La.elem,(La.listSize+LISTINCREMENT)*sizeof(ElemType)); La.listSize += LISTINCREMENT; } La.elem[i-1]=e; La.length++; } return OK; } void MergeList_Sq(SqList La,SqList Lb,SqList &Ld,SqList &Le) { //Ld是交,Le是補 ElemType* pa = La.elem; ElemType* pb = Lb.elem; Ld.length = 0; Ld.listSize = La.length + Lb.length; Ld.elem = (ElemType*)malloc(Ld.listSize*sizeof(ElemType)); ElemType* pd = Ld.elem; if(!Ld.elem) exit(OVERFLOW); Le.length = 0; Le.listSize = La.length + Lb.length; Le.elem = (ElemType*)malloc(Ld.listSize*sizeof(ElemType)); ElemType* pe = Le.elem; if(!Le.elem) exit(OVERFLOW); ElemType* pa_last = La.elem + La.length -1; ElemType* pb_last = Lb.elem + Lb.length -1; while(pa <= pa_last && pb <= pb_last) { if(*pa <= *pb) { if(*pa == *pb) { *pd++ = *pa; Ld.length++; } else { *pe++ = *pa; Le.length++; } // *pc++ = *pa++; pa++; } else { *pe++ = *pb; Le.length++; // *pc++ = *pb++; pb++; } } while(pa <= pa_last) { *pe++ = *pa; Le.length++; //*pc++ = *pa++; pa++; } while(pb <= pb_last){ *pe++ = *pb; Le.length++; // *pc++ = *pb++; pb++; } } void MergeList_Sq2(SqList La,SqList Lb,SqList &Lc) { int i,j; Lc.length = 0; Lc.listSize = La.length + Lb.length; Lc.elem = (ElemType*)malloc(Lc.listSize*sizeof(ElemType)); int n = 0; for(i = 0;i < La.length;i++){ j = 0; while((j < Lb.length)&&(La.elem[i] != Lb.elem[j])){ j++; } if(j == Lb.length){ Lc.elem[n] = La.elem[i]; ++Lc.length; ++n; } } } void ListPrint_Sq(SqList L){ if(L.length==0) { printf("\n"); } else { for(int i=0;i<L.length;++i){ if(i==0){ printf("%d",L.elem[i]); } else{ printf(" %d",L.elem[i]); } } printf("\n"); } } int main() { int num,i; scanf("%d",&num); for(i = 1;i <= num;i++) { SqList La,Lb,Ld,Le,Lf,Lg; InitList_Sq(La); InitList_Sq(Lb); int na,nb; scanf("%d",&na); CreateList(La,na); scanf("%d",&nb); CreateList(Lb,nb); MergeList_Sq(La,Lb,Ld,Le); MergeList_Sq2(La,Ld,Lf); MergeList_Sq2(Lb,Ld,Lg); printf("Case #%d:\n",i); //ListPrint_Sq(Lc); ListPrint_Sq(Ld); ListPrint_Sq(Le); ListPrint_Sq(Lf); ListPrint_Sq(Lg); } return 0; }