compareTo()方法返回值 String java
阿新 • • 發佈:2019-01-27
/** * Compares two strings lexicographically. * The comparison is based on the Unicode value of each character in * the strings. The character sequence represented by this * <code>String</code> object is compared lexicographically to the * character sequence represented by the argument string. The result is * a negative integer if this <code>String</code> object * lexicographically precedes the argument string. The result is a * positive integer if this <code>String</code> object lexicographically * follows the argument string. The result is zero if the strings * are equal; <code>compareTo</code> returns <code>0</code> exactly when * the {@link #equals(Object)} method would return <code>true</code>. * <p> * This is the definition of lexicographic ordering. If two strings are * different, then either they have different characters at some index * that is a valid index for both strings, or their lengths are different, * or both. If they have different characters at one or more index * positions, let <i>k</i> be the smallest such index; then the string * whose character at position <i>k</i> has the smaller value, as * determined by using the < operator, lexicographically precedes the * other string. In this case, <code>compareTo</code> returns the * difference of the two character values at position <code>k</code> in * the two string -- that is, the value: * <blockquote><pre> * this.charAt(k)-anotherString.charAt(k) * </pre></blockquote> * If there is no index position at which they differ, then the shorter * string lexicographically precedes the longer string. In this case, * <code>compareTo</code> returns the difference of the lengths of the * strings -- that is, the value: * <blockquote><pre> * this.length()-anotherString.length() * </pre></blockquote> * * @param anotherString the <code>String</code> to be compared. * @return the value <code>0</code> if the argument string is equal to * this string; a value less than <code>0</code> if this string * is lexicographically less than the string argument; and a * value greater than <code>0</code> if this string is * lexicographically greater than the string argument. */ public int compareTo(String anotherString) { int len1 = value.length; int len2 = anotherString.value.length; int lim = Math.min(len1, len2); char v1[] = value; char v2[] = anotherString.value; int k = 0; while (k < lim) { char c1 = v1[k]; char c2 = v2[k]; if (c1 != c2) { return c1 - c2; } k++; } return len1 - len2; }