Oracle 中如何手工提交Cluster Table的事務
阿新 • • 發佈:2019-01-27
環境中遇到了ora-00600 4000錯誤,涉及的物件即為cluster table,下面我這裡簡單模擬了一下。供參考!
++++建立測試表
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SQL> conn roger/roger Connected.
SQL> create
cluster t_cluster(id number(2)) ;
Cluster created.
SQL> create
table t_0610
2 (id number(2)
primary key ,
3
name varchar2(13))
4 cluster t_cluster(id);
Table
created.
SQL> create
index t_cluster_idx
on cluster t_cluster;
Index
created.
SQL> SQL> insert
into t_0610 values (1, 'baidu' );
1 row created.
SQL> insert
into t_0610 values (2, 'google' );
1 row created.
SQL> insert
into t_0610 values (8, 'roger' );
1 row created.
SQL> commit ;
Commit
complete.
SQL> select
* from
t_0610;
ID NAME
---------- ------------- 1 baidu
2 google
8 roger
SQL> select
dbms_rowid.rowid_relative_fno(rowid) file#,dbms_rowid.rowid_block_number(rowid) blk#
2
from t_0610;
FILE# BLK#
---------- ----------
6 172
6 173
6 174
SQL> oradebug setmypid
ORA-01031: insufficient
privileges
SQL> conn / as
sysdba
Connected.
SQL> oradebug setmypid
Statement processed.
SQL> alter
system flush buffer_cache;
System altered.
SQL> alter
system dump datafile 6 block 172;
System altered.
SQL> oradebug close_trace
Statement processed.
SQL> oradebug tracefile_name
/oracle/diag/rdbms/roger/roger/trace/roger_ora_16777.trc
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++++blockdump內容
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Dump of buffer cache at level 4 for tsn=7 rdba=25165996
BH (0x71bf2f28) file#: 6 rdba: 0x018000ac (6/172) class: 1 ba: 0x71ad8000
set: 3 pool: 3 bsz: 8192 bsi: 0 sflg: 2 pwc: 0,15
dbwrid: 0 obj: 77519 objn: 77520 tsn: 7 afn: 6 hint: f
hash: [0x8abfa738,0x8abfa738] lru: [0x74ff33a0,0x7abf47d0]
lru-flags: on_auxiliary_list
ckptq: [NULL] fileq: [NULL] objq: [NULL] objaq: [NULL]
st: FREE md: NULL fpin: 'ktspbwh2: ktspfmdb' tch: 0 lfb: 33
flags:
Block dump from disk:
buffer tsn: 7 rdba: 0x018000ac (6/172)
scn: 0x0000.00b941a6 seq: 0x01 flg: 0x06 tail: 0x41a60601
frmt: 0x02 chkval: 0xcb52 type: 0x06=trans data
Hex dump of block: st=0, typ_found=1
Dump of memory from 0x00007FADB771EA00 to 0x00007FADB7720A00
7FADB771EA00 0000A206 018000AC 00B941A6 06010000 [.........A......]
7FADB771EA10 0000CB52 00000001 00012ECF 00B94199 [R............A..]
7FADB771EA20 00000000 00320002 018000A8 00080006 [......2.........]
7FADB771EA30 00000515 00C00562 002E014E 00008000 [....b...N.......]
7FADB771EA40 00B94198 001D0007 000004C9 00C03C08 [.A...........<..]
7FADB771EA50 0032019D 00002001 00B941A6 00000000 [..2.. ...A......]
7FADB771EA60 00000000 00020201 001AFFFF 1F5E1F78 [............x.^.]
7FADB771EA70 00001F5E 00010001 1F820001 00001F78 [^...........x...]
7FADB771EA80 00000000 00000000 00000000 00000000 [................]
Repeat 500 times
7FADB77209D0 00000000 00000000 00000000 0001026C [............l...]
7FADB77209E0 69616205 00AC7564 01000101 00800100 [.baidu..........]
7FADB77209F0 010000AC 00AC0080 02C10200 41A60601 [...............A]
Block header dump: 0x018000ac
Object id on Block? Y
seg/obj: 0x12ecf csc: 0x00.b94199 itc: 2 flg: E typ: 1 - DATA
brn: 0 bdba: 0x18000a8 ver: 0x01 opc: 0
inc: 0 exflg: 0
Itl Xid Uba Flag Lck Scn/Fsc
0x01 0x0006.008.00000515 0x00c00562.014e.2e C--- 0 scn 0x0000.00b94198
0x02 0x0007.01d.000004c9 0x00c03c08.019d.32 --U- 1 fsc 0x0000.00b941a6
bdba: 0x018000ac
data_block_dump,data header at 0x7fadb771ea64
===============
tsiz: 0x1f98
hsiz: 0x1a
pbl: 0x7fadb771ea64
76543210
flag=-------K
ntab=2 ---- > 大於2,說明這是一個cluster table
nrow=2
frre=-1
fsbo=0x1a
fseo=0x1f78
avsp=0x1f5e
tosp=0x1f5e
0xe:pti[0] nrow=1 offs=0
0x12:pti[1] nrow=1 offs=1
0x16:pri[0] offs=0x1f82
0x18:pri[1] offs=0x1f78
block_row_dump:
tab 0, row 0, @0x1f82
tl: 22 fb: K-H-FL-- lb: 0x0 cc: 1
curc: 1 comc: 1 pk: 0x018000ac.0 nk: 0x018000ac.0
col 0: [ 2] c1 02
tab 1, row 0, @0x1f78
tl: 10 fb: -CH-FL-- lb: 0x2 cc: 1 cki: 0
col 0: [ 5] 62 61 69 64 75
end_of_block_dump
End dump data blocks tsn: 7 file#: 6 minblk 172 maxblk 172
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大家可以看到,這跟普通的data block的dump內容是有所差別的,因為這裡涉及到cluster table。
下面來模擬下手工提交cluster table的事務。
+++++模擬事務不提交
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SQL> alter
system checkpoint ;
System altered.
SQL> alter
system flush buffer_cache;
System altered.
SQL> show user
USER
is "SYS"
SQL> conn roger/roger
Connected.
SQL> delete
from t_0610 where
id=8; ++++++不提交
1 row deleted.
SQL> alter
system flush buffer_cache;
System altered.
SQL> select
xidusn,xidslot,xidsqn,ubablk,ubafil,ubarec from
v$ transaction ;
XIDUSN XIDSLOT XIDSQN UBABLK UBAFIL UBAREC
---------- ---------- ---------- ---------- ---------- ----------
3 17 1212 1066 3 20
SQL>
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這裡我們可以看到對於這個未提交的事務XID為:3.17.1212 前面我們已經知道
測試表中的資料分佈在3個block中,這裡我模擬的情況是刪除第3條資料,且不提交,通過bbed來實現手工
提交這個未提交事務,注意:第3條資料是在第3個block中,即174 block。
+++++首先修改表的itl等資訊
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BBED> set file 6 block 174
FILE# 6
BLOCK# 174
BBED> map
File: /oracle/oradata/roger/roger01.dbf (6)
Block: 174 Dba:0x018000ae
------------------------------------------------------------
KTB Data Block (Table/Cluster)
struct kcbh, 20 bytes @0
struct ktbbh, 72 bytes @20
struct kdbh, 14 bytes @100
struct kdbt[2], 8 bytes @114
sb2 kdbr[2] @122
ub1 freespace[8030] @126
ub1 rowdata[32] @8156
ub4 tailchk @8188
BBED> p kdbr
sb2 kdbr[0] @122 8066
sb2 kdbr[1] @124 8056
BBED> p ktbbh
struct ktbbh, 72 bytes @20
ub1 ktbbhtyp @20 0x01 (KDDBTDATA)
union ktbbhsid, 4 bytes @24
ub4 ktbbhsg1 @24 0x00012ecf
ub4 ktbbhod1 @24 0x00012ecf
struct ktbbhcsc, 8 bytes @28
ub4 kscnbas @28 0x00b94309
ub2 kscnwrp @32 0x0000
sb2 ktbbhict @36 2
ub1 ktbbhflg @38 0x32 (NONE)
ub1 ktbbhfsl @39 0x00
ub4 ktbbhfnx @40 0x018000a8
struct ktbbhitl[0], 24 bytes @44
struct ktbitxid, 8 bytes @44
ub2 kxidusn @44 0x0009
ub2 kxidslt @46 0x0002
ub4 kxidsqn @48 0x0000044c
struct ktbituba, 8 bytes @52
ub4 kubadba @52 0x00c000f9
ub2 kubaseq @56 0x014a
ub1 kubarec @58 0x1d
ub2 ktbitflg @60 0x8000 (KTBFCOM)
union _ktbitun, 2 bytes @62
sb2 _ktbitfsc @62 0
ub2 _ktbitwrp @62 0x0000
ub4 ktbitbas @64 0x00b941a4
struct ktbbhitl[1], 24 bytes @68
struct ktbitxid, 8 bytes @68
ub2 kxidusn @68 0x0003
ub2 kxidslt @70 0x0011
ub4 kxidsqn @72 0x000004bc
struct ktbituba, 8 bytes @76
ub4 kubadba @76 0x00c0042a
ub2 kubaseq @80 0x0185
ub1 kubarec @82 0x13
ub2 ktbitflg @84 0x0001 (NONE)
union _ktbitun, 2 bytes @86
sb2 _ktbitfsc @86 6
ub2 _ktbitwrp @86 0x0006
ub4 ktbitbas @88 0x00000000
BBED> modify /x 0180
Warning: contents of previous BIFILE will be lost. Proceed? (Y/N) y
File: /oracle/oradata/roger/roger01.dbf (6)
Block: 174 Offsets: 84 to 87 Dba:0x018000ae
------------------------------------------------------------------------
01800600
<32 bytes per line>
BBED> modify /x 00 offset 86
File: /oracle/oradata/roger/roger01.dbf (6)
Block: 174 Offsets: 86 to 87 Dba:0x018000ae
------------------------------------------------------------------------
0000
<32 bytes per line>
BBED> sum apply
Check value
for File 6, Block 174:
current = 0x055c, required = 0x055c
BBED> verify
DBVERIFY - Verification starting
FILE = /oracle/oradata/roger/roger01.dbf
BLOCK = 174
Block Checking: DBA = 25165998, Block Type = KTB-managed data block
data header at 0x7f88d49c1264
kdbchk: row locked by non-existent transaction
table=1 slot=0
lockid=2 ktbbhitc=2
Block 174 failed with check code 6101
BBED> p *kdbr[1]
rowdata[0]
----------
ub1 rowdata[0] @8156 0x7c
BBED> x /rnnnnccccccnnnnnnnnnnn
rowdata[0] @8156
----------
[email protected]: 0x7c (KDRHFL, KDRHFF, KDRHFD, KDRHFH, KDRHFC)
[email protected]: 0x02
[email protected]: 0
BBED> modify /x 6c offset 8156
File: /oracle/oradata/roger/roger01.dbf (6)
Block: 174 Offsets: 8156 to 8159 Dba:0x018000ae
------------------------------------------------------------------------
6c020100
<32 bytes per line>
BBED> sum apply
Check value
for File 6, Block 174:
current = 0x054c, required = 0x054c
BBED> verify
DBVERIFY - Verification starting
FILE = /oracle/oradata/roger/roger01.dbf
BLOCK = 174
Block Checking: DBA = 25165998, Block Type = KTB-managed data block
data header at 0x1112864
kdbchk: row locked by non-existent transaction
table=1 slot=0
lockid=2 ktbbhitc=2
Block 174 failed with check code 6101
DBVERIFY - Verification complete
Total Blocks Examined : 1
Total Blocks Processed (Data) : 1
Total Blocks Failing (Data) : 1
Total Blocks Processed (Index): 0
Total Blocks Failing (Index): 0
Total Blocks
Empty : 0
Total Blocks Marked Corrupt : 0
Total Blocks Influx : 0
Message 531 not found; product=RDBMS; facility=BBED
BBED> p kdbh
struct kdbh, 14 bytes @100
ub1 kdbhflag @100 0x01 (KDBHFFK)
sb1 kdbhntab @101 2
sb2 kdbhnrow @102 2
sb2 kdbhfrre @104 -1
sb2 kdbhfsbo @106 26
sb2 kdbhfseo @108 8056
sb2 kdbhavsp @110 8030
sb2 kdbhtosp @112 8040
BBED> d /v offset 102
count 4
File: /oracle/oradata/roger/roger01.dbf (6)
Block: 174 Offsets: 102 to 105 Dba:0x018000ae
-------------------------------------------------------
0200ffff l ....
<16 bytes per line>
BBED> modify /x 01 offset 102
File: /oracle/oradata/roger/roger01.dbf (6)
Block: 174 Offsets: 102 to 105 Dba:0x018000ae
------------------------------------------------------------------------
0100ffff
<32 bytes per line>
BBED> sum apply
Check value
for File 6, Block 174:
current = 0x054f, required = 0x054f
BBED> verify
DBVERIFY - Verification starting
FILE = /oracle/oradata/roger/roger01.dbf
BLOCK = 174
Block Checking: DBA = 25165998, Block Type = KTB-managed data block
data header at 0x1112864
kdbchk: fsbo(26) wrong, (hsz 24)
Block 174 failed with check code 6129
DBVERIFY - Verification complete
Total Blocks Examined : 1
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