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模擬,括號匹配——Parentheses Balance

You are given a string consisting of parentheses () and []. A string of this type is said to be correct:

(a)
if it is the empty string
(b)
if A and B are correct, AB is correct,
(c)
if A is correct, () and [] is correct.

Write a program that takes a sequence of strings of this type and check their correctness. Your program can assume that the maximum string length is 128.

Input 

The file contains a positive integer n and a sequence of n strings of parentheses () and [], one string a line.

A sequence of Yes or No on the output file.

3
([])
(([()])))
([()[]()])()
Yes
No
Yes
Miguel Revilla
2000-08-14
括號匹配,只要能成功匹配即可,注意輸出格式
#include <stdio.h>
#include <string.h>

int main()
{
    char st[1000];
    int n,m,i,j,k,len;
    char zhan[500];
    scanf("%d%*c",&n);
    while(n--)
    {
        k = 1;
        gets(st);
        len = strlen(st);
        int low = -1,high = -1;
        for(i = 0 ; i < len ; i++)
        {
            if(st[i] == '(' || st[i] == '[')
            {
                zhan[++high] = st[i];
            }
            else if(st[i] == ')')
            {
                if(zhan[high] == '(')
                    high--;
                else
                    {
                        printf("No\n");
                        k = 0;
                        break;
                    }
            }
            else if(st[i] == ']')
            {
                if(zhan[high] == '[')
                    high--;
                 else
                    {
                        printf("No\n");
                        k = 0;
                        break;
                    }
            }
        }
        if(i == len && high == -1)
            printf("Yes\n");
        else if(k == 1)
        {
            printf("No\n");
        }
    }
    return 0;
}