地圖座標糾偏及投影轉換的常見演算法
阿新 • • 發佈:2019-01-28
Web墨卡託座標與WGS84座標互轉
//經緯度轉墨卡託 -(CGPoint )lonLat2Mercator:(CGPoint ) lonLat { CGPoint mercator; double x = lonLat.x *20037508.34/180; double y = log(tan((90+lonLat.y)*M_PI/360))/(M_PI/180); y = y *20037508.34/180; mercator.x = x; mercator.y = y; return mercator ; } //墨卡託轉經緯度 -(CGPoint )Mercator2lonLat:(CGPoint ) mercator { CGPoint lonLat; double x = mercator.x/20037508.34*180; double y = mercator.y/20037508.34*180; y= 180/M_PI*(2*atan(exp(y*M_PI/180))-M_PI/2); lonLat.x = x; lonLat.y = y; return lonLat; }
火星座標系 (GCJ-02) 與百度座標系 (BD-09) 互轉
#include <math.h> const double x_pi = 3.14159265358979324 * 3000.0 / 180.0; //將 GCJ-02 座標轉換成 BD-09 座標 void bd_encrypt(double gg_lat, double gg_lon, double &bd_lat, double &bd_lon) { double x = gg_lon, y = gg_lat; double z = sqrt(x * x + y * y) + 0.00002 * sin(y * x_pi); double theta = atan2(y, x) + 0.000003 * cos(x * x_pi); bd_lon = z * cos(theta) + 0.0065; bd_lat = z * sin(theta) + 0.006; } void bd_decrypt(double bd_lat, double bd_lon, double &gg_lat, double &gg_lon) { double x = bd_lon - 0.0065, y = bd_lat - 0.006; double z = sqrt(x * x + y * y) - 0.00002 * sin(y * x_pi); double theta = atan2(y, x) - 0.000003 * cos(x * x_pi); gg_lon = z * cos(theta); gg_lat = z * sin(theta); }
簡單演算法(lat和lng是經緯度,球面座標):
//To_B是轉到百度,To_G是轉到GCJ-02。
var TO_BLNG = function(lng){return lng+0.0065;};
var TO_BLAT = function(lat){return lat+0.0060;};
var TO_GLNG = function(lng){return lng-0.0065;};
var TO_GLAT = function(lat){return lat-0.0060;};
GPS轉換為GCJ-02座標
https://www.google.com.hk/search?q=wgtochina_lb&hl=zh-CN
參考資料:
- http://bbs.esrichina-bj.cn/esri/viewthread.php?tid=78245
- http://blog.csdn.net/coolypf/article/details/8569813
- http://www.cnblogs.com/milkmap/p/3627940.html
- http://www.cnblogs.com/milkmap/p/3768379.html