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求最近公共祖先和所有祖先

#include "btree.cpp" //二叉鏈的基本運算
#include<iostream>

using namespace std;

bool allAncestor(BTNode *b, ElemType t)//求所有祖先節點
{
    if (b == NULL)
        return false;
    else if ((b->lchild != NULL && b->lchild->data == t) || (b->rchild != NULL && b->rchild->data ==
t)) { cout<< b->data<<" "; return true; } else if (allAncestor(b->lchild, t) || allAncestor(b->rchild, t)) { cout<< b->data<<" "; return true; } else return false; } BTNode *nearestAncestor(BTNode *
b,ElemType x,ElemType y)//求x和y的最近公共祖先 { if(b==NULL || b->data==x || b->data==y) return b; BTNode *left=nearestAncestor(b->lchild,x,y); BTNode *right=nearestAncestor(b->rchild,x,y); if(left!=NULL && right!=NULL) return b; else if(left!=NULL) return
left;//等價於left!=NULL && right==NULL else return right;//等價於left==NULL && right!=NULL或者left==NULL && right==NULL } int main() { BTNode *b; ElemType x = 'F', y = 'H'; CreateBTNode(b,"A(B(D,E),C(F,G(,H)))"); cout<<"二叉樹b為:";DispBTNode(b);cout<<endl; cout<<"結點"<<x<<"和"<<y<<"的最近公共祖先為:"<<nearestAncestor(b,x,y)->data<<endl; cout<<"結點"<<y<<"的所有祖先為:";allAncestor(b, y);cout<<endl; return 0; }

這裡寫圖片描述