2-1 快樂數字

def snum(num):
    strnum = str(num)
    sum = 0
    b = [int(x) for x in strnum]
    for i in b:
        sum += i**2
    return sum

def main():
    a = input()
    num = eval(a)
    count = 0
    while num != 1:
        num = snum(num)
        count += 1
        if count > 2000:
            print("False")
            break
    else:
            print("True")

main()
 

2-2數列階乘相加

a = input()
sum = 0
if a.isdigit():
    num = eval(a)
    if num > 0:
        count = 1
        for i in range(1, num+1):
            count *= i
            sum += count
        print(sum)
    else:
        print("輸入有誤，請輸入正整數")
else:
    print("輸入有誤，請輸入正整數")

2-3成績轉換輸入

try:
    a = eval(input())
except:
    print('輸入資料有誤！')
else:
    if 0 <= a < 60:
        print('輸入成績屬於E級別。')
    elif 60 <= a < 70:
        print('輸入成績屬於D級別。')
        print('祝賀你通過考試！')
    elif 70 <= a < 80:
        print('輸入成績屬於C級別。')
        print('祝賀你通過考試！')
    elif 80 <= a < 90:
        print('輸入成績屬於B級別。')
        print('祝賀你通過考試！')
    elif 90 <= a <= 100:
        print('輸入成績屬於A級別。')
        print('祝賀你通過考試！')
    else:
        print('輸入資料有誤！')
finally:
    print('好好學習，天天向上！')
 

def fblq(n):
    if n == 0:
        m = 0
    elif n == 1:
        m = 1
    else:
        m = fblq(n - 1) + fblq(n - 2)
    return m

def main():
    a = eval(input())
    sum = 0
    fblq_list = []
    for i in range(0, a+1):
        print('{}, '.format(fblq(i)),end='')
        sum += fblq(i)
    equal = sum / (a+1)
    print('{}, {:.0f}'.format(sum, equal))

main()
 

from operator import itemgetter
queue = eval(input())
 
queue.sort(key = itemgetter(1))
#print(queue)
queue.sort(key = itemgetter(0), reverse = True)
#print(queue)
 
output = []
for item in queue:
    output.insert(item[1], item)
    #print(output)
print(output)

# 排列組合的問題，但是真的不容易實現，參考了https://blog.csdn.net/gaozhenweigzw/article/details/44781705

def PLZH(lst, ch, a, b):
    if (a == 0) and (b == 0):
        lst.append(ch)
        return(lst)
    if a > 0:
        PLZH(lst, ch + '(', a-1,b + 1)
    if b > 0:
        PLZH(lst, ch + ')', a, b - 1)
 
a = eval(input())
b = 0
lst = []
ch = ''
PLZH(lst, ch, a, b)
print(lst)

count = 0
for i in range (0, 3):
    count += 1
    judge_n = input()
    judge_c = input()
    if judge_n == "Kate" and judge_c == "666666":
        print("登入成功！")
        bool = False
        break
if bool:
    print("3次使用者名稱或者密碼均有誤！退出程式。")

期末考試（比測驗簡單多了）

凱撒密碼B

PassInit = input()
for ind in PassInit:
    if (ord('a') <= ord(ind) <= ord('z')):
        PassKaisa = chr(ord('a')+(ord(ind)-ord('a')+3)%26)
        print(PassKaisa,end='')
    elif  (ord('A') <= ord(ind) <= ord('Z')):
        PassKaisa = chr(ord('A')+(ord(ind)-ord('A')+3)%26)
        print(PassKaisa,end='')
    else:
        PassKaisa = ind
        print(PassKaisa,end='')
        continue

水仙花數

sxhnum = []
for i in range (100, 1000):
    A = i // 100
    B = i // 10 % 10
    C = i % 10
    if A**3 + B**3 + C**3 == i:
        sxhnum.append(i)
    else:
        continue
len_num = len(sxhnum)
for j in range (len_num):
    if j < len_num - 1:
        print('{},'.format(sxhnum[j]),end='')
    else:
        print('{}'.format(sxhnum[j]))

心裡話

這題有問題直接  print("李安，我想對你說，你真有才！")  就 AC 了。

a = input()
b = input()
str1 = a + '，我想對你說，' + b
print(str1)

字串垂直輸出

str = input()
for i in str:
    print(i)

哈姆雷特詞頻統計

def getText():
    txt = open("hamlet.txt", "r").read()
    txt = txt.lower()
    for ch in '!"#$%&()*+,-./:;<=>[email protected][\\]^_‘{|}~':
        txt = txt.replace(ch, " ")
    return txt
 
hamletTxt = getText()
words  = hamletTxt.split()
counts = {}
for word in words:           
    counts[word] = counts.get(word,0) + 1
items = list(counts.items())
items.sort(key=lambda x:x[1], reverse=True) 
for i in range(10):
    word, count = items[i]
    print ("{:<10},{:>5}".format(word, count))