Mars: Nasa lands InSight robot to study planet's interior
The US space agency Nasa has landed a new robot on Mars after a dramatic seven-minute plunge to the surface of the Red Planet. The InSight probe aims to study the world's deep interior, and make it the only planet - apart from Earth - that has been examined in this way. Confirmation of touchdown came through on cue at 19:53 GMT. It ended an anxious wait in which the robot radioed home a series of updates on its descent. Nasa's mission control at California's Jet Propulsion Laboratory (JPL) erupted into cheers when it became clear InSight was safe on the ground.
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how to study reinforcement learning(answered by Sergio Valcarcel Macua on Quora)
work asi -a recommend practical man glob alua iteration link: https://www.quora.com/What-are-the-best-books-about-reinforcement-learning
ACM-ICPC 2018 徐州賽區網絡預賽 H. Ryuji doesn't want to study （線段樹）
ace esp repr for lin n) mat put 鏈接 Ryuji is not a good student, and he doesn‘t want to study. But there are n books he should learn, each
Ryuji doesn't want to study 2018徐州icpc網絡賽 樹狀數組
vertical 題目 date cpc ear typedef -a void return Ryuji is not a good student, and he doesn‘t want to study. But there are n books he shou
2018徐州網絡賽H. Ryuji doesn't want to study
problem test case numeric -html mac ros posit cpp tex 題目鏈接： https://nanti.jisuanke.com/t/31458 題解： 建立兩個樹狀數組，第一個是，a[1]*n+a[2]*(n-1).
ACM-ICPC 2018徐州網絡賽-H題 Ryuji doesn't want to study
als ryu using 網絡 nan spa upd div names C*M....死於update的一個long long寫成int了 心累 不想寫過程了 ******** 樹狀數組，一個平的一個斜著的，怎麽斜都行 題庫鏈接：https://nanti.ji
ACM-ICPC 2018 徐州賽區網絡預賽 H Ryuji doesn't want to study (樹狀數組差分)
() clas targe anti icpc -- nbsp nan ant https://nanti.jisuanke.com/t/31460 題意 兩個操作。1：查詢區間[l,r]的和，設長度為L=r-l+1， sum=a[l]*L+a[l+1]*(L-1)+.
ACM-ICPC 2018 徐州賽區網路預賽 H. Ryuji doesn't want to study （線段樹維護字首和的字首和）
題意 很簡答就是每次查詢 (L,R)的時候 ，查詢 a[L]∗(R−L+1)+a[L+1]∗(R−L−1)+a[L+2]∗(R−L−2)....a[R]∗1 a [
[ACM-ICPC 2018 徐州賽區網路預賽] Ryuji doesn't want to study [線段樹]
Problem Describe Ryuji is not a good student, and he doesn’t want to study. But there are n books he should learn, each book has its knowledge
2018 icpc徐州站網路賽 H ——Ryuji doesn't want to study ——（線段樹）
題目連結:https://nanti.jisuanke.com/t/31460 題目思路：很明顯的一個線段樹題目，但是要求的是a[l]*len+a[l+1]*(len-1)+a[l+2]*(len-2)+......+a[r]，所以根據這個推得以下公式： 可以試著推一下這個公式。所以我們維護
徐州H-Ryuji doesn't want to study【線段樹】
Ryuji is not a good student, and he doesn't want to study. But there are n books he should learn, each book has its knowledge a[i]a[i]. U
Ryuji doesn't want to study（線段樹）
Ryuji is not a good student, and he doesn't want to study. But there are n books he should learn, each book has its knowledge a[i]a[i]. U
ACM-ICPC 2018 徐州賽區網路預賽 H. Ryuji doesn't want to study （線段樹維護字首和的字首和）
題意 很簡答就是每次查詢 (L,R)的時候 ，查詢 a[L]∗(R−L+1)+a[L+1]∗(R−L−1)+a[L+2]∗(R−L−2)....a[R]∗1a[L]∗(R−L+1)+a[L+1]∗(R−L−1)+a[L+2]∗(R−L−2)....a[R]∗1
Ryuji doesn't want to study-線段樹應用
#include<bits/stdc++.h> using namespace std; #define maxn 500000 #define ll long long struct node { int l,r,sum; } root[maxn],tr
ACM-ICPC 2018 徐州賽區網路預賽 H. Ryuji doesn't want to study 【線段樹】
1000ms 262144K Ryuji is not a good student, and he doesn't want to study. But there are n books he should learn, each book has its know
計蒜客 Ryuji doesn't want to study（2018 ICPC 徐州 網路賽 ）線段樹
Ryuji is not a good student, and he doesn't want to study. But there are n books he should learn, each book has its knowledge a[i]a[i]. U