leetcode 191 Number of 1 Bits 位1的個數 python 多種思路,最簡程式碼(字串轉化內建函式 ,位運算)
class Solution(object):
def hammingWeight(self, n):
"""
:type n: int
:rtype: int
"""
# method one 用內建函式
# return bin(n).count('1')
# method two 用位操作
num = 0
while n:
num += n % 2
n //= 2
return num
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class Solution(object): def hammingWeight(self, n): """ :type n: int :rty
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