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I know that switch/select statements break automatically after every case. I am wondering, in the following code:

for {
    switch sometest() {
    case 0:
        dosomething()
    case 1:
        break
    default:
        dosomethingelse()
    }
}

Does the break statement exit the for loop or just the switch

asked Jun 19 '12 at 15:16

Matt

9,254104491

7 Answers

A "break" statement terminates execution of the innermost "for", "switch" or "select" statement.

BreakStmt = "break" [ Label ] .

If there is a label, it must be that of an enclosing "for", "switch" or "select" statement, and that is the one whose execution terminates (§For statements, §Switch statements, §Select statements).

L:
  for i < n {
      switch i {
      case 5:
          break L
      }
  }

Therefore, the break statement in your example terminates the switch statement, the "innermost" statement.

answered Jun 19 '12 at 16:41

83.7k13149164

A hopefully illustrative example:

loop:
for {
        switch expr {
        case foo:
                if condA {
                        doA()
                        break // like 'goto A'
                }

                if condB {
                        doB()
                        break loop // like 'goto B'                        
                }

                doC()
        case bar:
                // ...
        }
A:
        doX()
        // ...
}

B:
doY()
// ....