LintCode-Fizz Buzz問題
阿新 • • 發佈:2019-02-05
- 描述
給你一個整數n. 從 1 到 n 按照下面的規則列印每個數:
如果這個數被3整除,列印fizz.
如果這個數被5整除,列印buzz.
如果這個數能同時被3和5整除,列印fizz buzz. - 樣例
比如 n = 15, 返回一個字串陣列:
[
“1”, “2”, “fizz”,
“4”, “buzz”, “fizz”,
“7”, “8”, “fizz”,
“buzz”, “11”, “fizz”,
“13”, “14”, “fizz buzz”
] - 程式碼
class Solution {
public:
/**
* param n: As description.
* return: A list of strings.
*/
vector<string> fizzBuzz(int n) {
vector<string> results;
for(int i=1;i<=n;i++)
{
if(i%5==0&&i%3==0)
results.push_back("fizz buzz");
else if(i%5==0)
results.push_back("buzz");
else if(i%3 ==0)
results.push_back("fizz");
else
results.push_back(to_string(i));
}
return results;
}
};