矩陣原地轉置,空間複雜度為O(1)(暫時先儲存下來)
阿新 • • 發佈:2019-02-05
#include<iostream>
using namespace std;
/* 後繼 */
int getNext(int i, int m, int n)
{
return (i%n)*m + i/n;
}
/* 前驅 */
int getPre(int i, int m, int n)
{
return (i%m)*n + i/m;
}
/* 處理以下標i為起點的環 */
void movedata(int *mtx, int i, int m, int n)
{
int temp = mtx[i]; // 暫存
int cur = i; // 當前下標
int pre = getPre(cur, m, n);
while(pre != i)
{
mtx[cur] = mtx[pre];
cur = pre;
pre = getPre(cur, m, n);
}
mtx[cur] = temp;
}
/* 轉置,即迴圈處理所有環 */
void transpose(int *mtx, int m, int n)
{
for(int i=0; i<m*n; ++i)
{
int next = getNext(i, m, n);
while (next > i) // 若存在後繼小於i說明重複
next = getNext(next, m, n);
if(next == i) // 處理當前環
movedata(mtx, i, m, n);
}
}
/* 輸出矩陣 */
void print(int *mtx, int m, int n)
{
for(int i=0; i<m*n; ++i)
{
if((i+1)%n == 0)
cout << mtx[i] << "\n";
else
cout << mtx[i] << " ";
}
}
/* 測試 */
int main()
{
int matrix[4*2] = {1,2,3,4,5,6,7,8};
cout << "Before matrix transposition:" << endl;
print(matrix, 4, 2);
transpose(matrix, 4, 2);
cout << "After matrix transposition:" << endl;
print(matrix, 2, 4);
return 0;
}