淺析std::remove函式
阿新 • • 發佈:2019-02-08
c++標準庫中有一個名為 std::remove函式,形式為
remove(beg,end,val)
remove_if(beg,end,unarryPred)
其中,beg,end為迭代器,也可以為指標
機理為:通過用儲存的元素覆蓋元素而從序列中“移去”元素。remove移去的元素為等於val值,remove_if移去的是當unarryPred為真的那些元素,然後返回一個迭代器,該迭代器指向未移去的最後一個元素的下一個位置。
我們需要注意的是,remove函式是通過覆蓋移去的,如果容器最後一個值剛好是需要刪除的,則它無法覆蓋掉容器中最後一個元素!我們來看下面一個例子,取自msdn
// remove.cpp // compile with: /EHsc // Illustrates how to use the remove function. // // Functions: // remove - remove all elements from the sequence that match value. // begin - Returns an iterator that points to the first element in a // sequence. // end - Returns an iterator that points one past the end of a sequence. ////////////////////////////////////////////////////////////////////// // disable warning C4786: symbol greater than 255 character, // okay to ignore #pragma warning(disable: 4786) #include <iostream> #include <vector> #include <algorithm> #include <functional> using namespace std; int main() { const int VECTOR_SIZE = 8 ; // Define a template class vector of integers typedef vector<int > IntVector ; //Define an iterator for template class vector of integer typedef IntVector::iterator IntVectorIt ; IntVector Numbers(VECTOR_SIZE) ; //vector containing numbers IntVectorIt start, end, it, last; start = Numbers.begin() ; // location of first // element of Numbers end = Numbers.end() ; // one past the location // last element of Numbers //Initialize vector Numbers Numbers[0] = 10 ; Numbers[1] = 20 ; Numbers[2] = 10 ; Numbers[3] = 15 ; Numbers[4] = 12 ; Numbers[5] = 7 ; Numbers[6] = 9 ; Numbers[7] = 10 ; cout << "Before calling remove" << endl ; // print content of Numbers cout << "Numbers { " ; for(it = start; it != end; it++) cout << *it << " " ; cout << " }\n" << endl ; // remove all elements from Numbers that match 10 last = remove(start, end, 10) ; cout << "After calling remove" << endl ; // print content of Numbers cout << "Numbers { " ; for(it = start; it != end; it++) cout << *it << " " ; cout << " }\n" << endl ; //print number of elements removed from Numbers cout << "Total number of elements removed from Numbers = " << end - last << endl ; //print only the valid elements of Number cout << "Valid elements of Numbers { " ; for(it = start; it != last; it++) cout << *it << " " ; cout << " }\n" << endl ; }
Before calling remove Numbers { 10 20 10 15 12 7 9 10 } After calling remove Numbers { 20 15 12 7 9 7 9 10 } //我們可以看到,這邊最後一個元素 Total number of elements removed from Numbers = 3 Valid elements of Numbers { 20 15 12 7 9 }
第二個結果很有意思的,結果並不是20 15 12 7 9 9 9 10,從這裡我們也可以發現,remove實現機制是統一先找出哪些元素需要被覆蓋,等全部找到以後在進行一次性覆蓋,而不是每找到一個需要覆蓋的元素就將其進行覆蓋。因為我們知道,對於順序儲存的容器如vectro deque 來說,移動覆蓋代價是很大的,所以這麼做完全是從效能上來考慮的。