Swap Nodes in Pairs 連結串列交換相鄰的節點
阿新 • • 發佈:2019-02-09
Given a linked list, swap every two adjacent nodes and return its head.
For example,
Given 1->2->3->4
, you should return the list as 2->1->4->3
.
Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *swapPairs(ListNode *head) { if(head==NULL||head->next==NULL) { return head; } int temp; ListNode *p=head; while(p&&p->next) { temp=p->val; p->val=p->next->val; p->next->val=temp; p=p->next; p=p->next; } return head; } };