Java8使List轉為Map
阿新 • • 發佈:2019-02-10
import com.yang.test.User; import javax.jws.soap.SOAPBinding; import java.util.*; import java.util.function.Function; import java.util.stream.Collectors; public class Main { public static void main(String[] args) { List<User> userlist = new ArrayList<>(); for (int i = 0; i <10; i++) { userlist.add(new User("張三"+i,i)); } System.out.println(getAllages(userlist).size()); System.out.println(getUser2Map(userlist)); System.out.println(getUser2MapUser(userlist)); System.out.println(getUser2MapUser2(userlist)); System.out.println(getUser2MapUser3(userlist)); } public static List<Integer> getAllages(List<User>userlist){ return userlist.stream().map(user -> user.getAge()).collect(Collectors.toList()); } public static Map<Integer,String> getUser2Map(List<User>userlist){ return userlist.stream().collect(Collectors.toMap(User::getAge,User::getName)); } public static Map<Integer,User> getUser2MapUser(List<User>userlist){ return userlist.stream().collect(Collectors.toMap(User::getAge,User-> User)); } /** * 比較優雅的寫法是這樣的 * @param userlist * @return */ public static Map<Integer,User> getUser2MapUser2(List<User>userlist){ return userlist.stream().collect(Collectors.toMap(User::getAge, Function.identity())); } /** * 重複key的情況下 簡單的使用後者覆蓋前者的 */ public static Map<Integer,User> getUser2MapUser3(List<User>userlist){ return userlist.stream().collect(Collectors.toMap(User::getAge, Function.identity(),(key1,key2)->key2)); } /** *指定map的具體實現 * @param userlist * @return */ public static Map<Integer,User> getUser2MapUser4(List<User>userlist){ return userlist.stream().collect(Collectors.toMap(User::getAge, Function.identity(),(key1,key2)->key2, LinkedHashMap::new)); } }