[Swift]LeetCode605. 種花問題 | Can Place Flowers
阿新 • • 發佈:2019-03-01
包含 rule which 數組 code solution long () ini
Runtime: 128 ms Memory Usage: 19.3 MB
Suppose you have a long flowerbed in which some of the plots are planted and some are not. However, flowers cannot be planted in adjacent plots - they would compete for water and both would die.
Given a flowerbed (represented as an array containing 0 and 1, where 0 means empty and 1 means not empty), and a number n, return if n new flowers can be planted in it without violating the no-adjacent-flowers rule.
Example 1:
Input: flowerbed = [1,0,0,0,1], n = 1 Output: True
Example 2:
Input: flowerbed = [1,0,0,0,1], n = 2 Output: False
Note:
- The input array won‘t violate no-adjacent-flowers rule.
- The input array size is in the range of [1, 20000].
- n is a non-negative integer which won‘t exceed the input array size.
假設你有一個很長的花壇,一部分地塊種植了花,另一部分卻沒有。可是,花卉不能種植在相鄰的地塊上,它們會爭奪水源,兩者都會死去。
給定一個花壇(表示為一個數組包含0和1,其中0表示沒種植花,1表示種植了花),和一個數 n 。能否在不打破種植規則的情況下種入 n 朵花?能則返回True,不能則返回False。
示例 1:
輸入: flowerbed = [1,0,0,0,1], n = 1 輸出: True
示例 2:
輸入: flowerbed = [1,0,0,0,1], n = 2 輸出: False
註意:
- 數組內已種好的花不會違反種植規則。
- 輸入的數組長度範圍為 [1, 20000]。
- n 是非負整數,且不會超過輸入數組的大小。
Runtime: 128 ms Memory Usage: 19.3 MB
1 class Solution { 2 func canPlaceFlowers(_ flowerbed: [Int], _ n: Int) -> Bool { 3 var flowerbed = flowerbed 4 var n = n 5 flowerbed.insert(0,at:0) 6 flowerbed.append(0) 7 var i:Int = 1 8 while(i < flowerbed.count - 1) 9 { 10 if n == 0 {return true} 11 if flowerbed[i - 1] + flowerbed[i] + flowerbed[i + 1] == 0 12 { 13 n -= 1 14 i += 1 15 } 16 i += 1 17 } 18 return n <= 0 19 } 20 }
132ms
1 class Solution { 2 func canPlaceFlowers(_ flowerbed: [Int], _ n: Int) -> Bool { 3 if n == 0{ 4 return true 5 } 6 var pending = n 7 8 var currentIndex = 0 9 var foundOne = false 10 while currentIndex < flowerbed.count{ 11 if flowerbed[currentIndex] == 0{ 12 if foundOne || (currentIndex < flowerbed.count - 1 && flowerbed[currentIndex + 1] == 1){ 13 foundOne = false 14 currentIndex += 1 15 } 16 else{ 17 pending -= 1 18 if pending == 0{ 19 return true 20 } 21 currentIndex += 2 22 } 23 } 24 else if flowerbed[currentIndex] == 1{ 25 foundOne = true 26 currentIndex += 1 27 } 28 else{ 29 currentIndex += 1 30 } 31 } 32 return pending == 0 33 } 34 }
136ms
1 class Solution { 2 func canPlaceFlowers(_ flowerbed: [Int], _ n: Int) -> Bool { 3 guard n > 0 else { 4 return true 5 } 6 7 var left = n 8 var newArray = [0] 9 newArray.append(contentsOf: flowerbed) 10 newArray.append(0) 11 var i = 0 12 while i < newArray.count - 2 { 13 if newArray[i] == 0 && newArray[i+1] == 0 && newArray[i+2] == 0 { 14 left -= 1 15 i += 1 16 if left == 0 { 17 return true 18 } 19 } 20 i += 1 21 } 22 return left == 0 23 } 24 }
140ms
1 class Solution { 2 func canPlaceFlowers(_ flowerbed: [Int], _ n: Int) -> Bool { 3 var flowerbed = flowerbed 4 var n = n 5 var i = 0 6 while i < flowerbed.count && n > 0 { 7 if flowerbed[i] == 0 && (i == 0 || flowerbed[i - 1] == 0) && (i == flowerbed.count - 1 || flowerbed[i + 1] == 0) { 8 n -= 1 9 flowerbed[i] = 1 10 } 11 i += 1 12 } 13 return n == 0 14 } 15 }
144ms
1 class Solution { 2 func canPlaceFlowers(_ flowerbed: [Int], _ n: Int) -> Bool { 3 var result = 0 4 var count = 1 5 for b in flowerbed { 6 if b == 0 { 7 count += 1 8 } else if b == 1 { 9 result += (count-1)/2 10 count = 0 11 } 12 } 13 result += count / 2 14 return result >= n 15 } 16 }
152ms
1 class Solution { 2 func canPlaceFlowers(_ flowerbed: [Int], _ n: Int) -> Bool { 3 if n == 0 {return true} 4 5 6 var pre = -2 7 var count = n 8 for (index, num) in flowerbed.enumerated() { 9 if num == 1 { 10 count -= (index - pre - 1 - 1) / 2 11 pre = index 12 } 13 } 14 count -= (flowerbed.count - pre - 1) / 2 15 return count <= 0 16 } 17 }
172ms
1 class Solution { 2 func canPlaceFlowers(_ flowerbed: [Int], _ n: Int) -> Bool { 3 // how many possible position 4 var adjcent = 0 5 // how many consequent 0 start with 1 because plant can be placed at first position it means the left of first position. 6 var c = 1 7 for i in 0..<flowerbed.count{ 8 if flowerbed[i] == 0 { 9 c += 1 10 }else{ 11 adjcent += (c-1)/2 12 c = 0 13 } 14 } 15 // last consequent 0 won‘t be calculated within the loop if last position is 0. Like first position, last position‘right is 0 as well. 16 adjcent += c/2 17 return adjcent >= n 18 } 19 }
180ms
1 class Solution { 2 func canPlaceFlowers(_ flowerbed: [Int], _ n: Int) -> Bool { 3 var flowerPlaced = 0 4 5 var lastOne = -1 6 var i = 0 7 while i < flowerbed.count { 8 while i < flowerbed.count && flowerbed[i] == 0 { 9 i += 1 10 } 11 12 let space = i - lastOne - 1 13 14 if lastOne >= 0 && i < flowerbed.count { 15 flowerPlaced += (space - 1) / 2 16 } else if lastOne == -1 && i == flowerbed.count { 17 flowerPlaced += (space + 1) / 2 18 } else { 19 flowerPlaced += space / 2 20 } 21 22 if flowerPlaced >= n { 23 return true 24 } 25 26 while i < flowerbed.count && flowerbed[i] == 1 { 27 i += 1 28 } 29 lastOne = i - 1 30 } 31 32 return false 33 } 34 }
196ms
1 class Solution { 2 func canPlaceFlowers(_ flowerbed: [Int], _ n: Int) -> Bool { 3 var planted = 0 4 5 var space = 1 6 7 for plot in flowerbed { 8 if plot == 0 { 9 space += 1 10 } else { 11 planted += (space - 1) / 2 12 space = 0 13 } 14 } 15 16 return (planted + space / 2) >= n 17 } 18 }
[Swift]LeetCode605. 種花問題 | Can Place Flowers