基礎的字符串操作,用兩個指針掃一遍就行.

class Solution(object):
    def compress(self,chars):
        """
        :type chars: List[str]
        :rtype: int
        """
        if not chars:
            return 0
        if len(chars) == 1:
            return 1
        left, right, num = 0, 1, 1
        while
 
 right <= len(chars):
            if right == len(chars):
                if num > 1:
                    chars[left:right] = chars[left] + str(num)
                break
            if chars[right] == chars[left]:
                num += 1
                right += 1
            elif num > 1:  #
 
 need modification
                chars[left:right] = chars[left] + str(num)
                left = left + len(chars[left] + str(num))
                right = left + 1
                num = 1
            else:
                left = right
                right = left + 1
        print(chars)
        
 
return len(chars)

Leetcode 443 String Compression