LeetCode-36.Valid Sudoku
阿新 • • 發佈:2019-03-29
commons 分享圖片 odi i++ ces tco load exc htm
Determine if a 9x9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules:
- Each row must contain the digits
1-9
without repetition. - Each column must contain the digits
1-9
without repetition. - Each of the 9
3x3
sub-boxes of the grid must contain the digits1-9
A partially filled sudoku which is valid.
The Sudoku board could be partially filled, where empty cells are filled with the character ‘.‘
.
Example 1:
Input: [ ["5","3",".",".","7",".",".",".","."], ["6",".",".","1","9","5",".",".","."], [".","9","8",".",".",".",".","6","."], ["8",".",".",".","6",".",".",".","3"], ["4",".",".","8",".","3",".",".","1"], ["7",".",".",".","2",".",".",".","6"], [".","6",".",".",".",".","2","8","."], [".",".",".","4","1","9",".",".","5"], [".",".",".",".","8",".",".","7","9"] ] Output: true
Example 2:
Input: [ ["8","3",".",".","7",".",".",".","."], ["6",".",".","1","9","5",".",".","."], [".","9","8",".",".",".",".","6","."], ["8",".",".",".","6",".",".",".","3"], ["4",".",".","8",".","3",".",".","1"], ["7",".",".",".","2",".",".",".","6"], [".","6",".",".",".",".","2","8","."], [".",".",".","4","1","9",".",".","5"], [".",".",".",".","8",".",".","7","9"] ] Output: false Explanation: Same as Example 1, except with the 5 in the top left corner being modified to 8. Since there are two 8‘s in the top left 3x3 sub-box, it is invalid.
Note:
- A Sudoku board (partially filled) could be valid but is not necessarily solvable.
- Only the filled cells need to be validated according to the mentioned rules.
- The given board contain only digits
1-9
and the character‘.‘
. - The given board size is always
9x9
.
判斷每行 每列和每個3*3方塊中有沒有重復的
1 public boolean isValidSudoku(char[][] board) {//set mytip 2 Set<String> set = new HashSet<>(); 3 for (int i = 0; i < board.length; i++) { 4 for (int j = 0; j < board.length; j++) { 5 if (‘.‘!=board[i][j]){ 6 String s1 = board[i][j]+"-"+i; 7 String s2 = board[i][j]+"|"+j; 8 String s3 = board[i][j]+"#"+(i/3*3+j/3); 9 if(set.contains(s1)||set.contains(s2)||set.contains(s3)){ 10 return false; 11 } 12 else{ 13 set.add(s1); 14 set.add(s2); 15 set.add(s3); 16 } 17 } 18 } 19 } 20 return true; 21 }
進階題
數獨 LeetCode37 https://www.cnblogs.com/zhacai/p/10622800.html
LeetCode-36.Valid Sudoku