通過中序和前序遍歷重建二叉樹
阿新 • • 發佈:2019-04-14
import java.util.*;
class TreeNode{
int val;
TreeNode left;
TreeNode right;
TreeNode(int val){
this.val =val;
}
}
public class binary {
public static void main(String args[]) {
int[] a={1,2,4,7,3,5,6,8};
int[] b={4,7,2,1,5,3,8,6};
reConstructBinaryTree(a,b);
}
public static TreeNode reConstructBinaryTree(int [] pre,int [] in) {
TreeNode root=reConstructBinaryTree(pre,0,pre.length-1,in,0,in.length-1);
return root;
} //前序遍歷{1,2,4,7,3,5,6,8}和中序遍歷序列{4,7,2,1,5,3,8,6}
private static TreeNode reConstructBinaryTree(int [] pre,int startPre,int endPre,int [] in,int startIn,int endIn) {
if(startPre>endPre||startIn>endIn)
return null;
TreeNode root=new TreeNode(pre[startPre]);
System.out.println(root.val);
for(int i=startIn;i<=endIn;i++)
if(in[i]==pre[startPre]){
root.left=reConstructBinaryTree(pre,startPre+1,startPre+i-startIn,in,startIn,i-1);
root.right=reConstructBinaryTree(pre,i-startIn+startPre+1,endPre,in,i+1,endIn);
}
return root;