#include <iostream>
#include <string>
using namespace std;
int main(){
    int n;
    string str;
    cin >> n;
    getchar();
    while (n--){
        int str_num = 0, str_letter = 0, str_dot = 0, str_other = 0;
        getline(cin, str);
        if (str.size() < 6)
            cout 
 
<< "Your password is tai duan le." << endl;
        else{
            for (int i = 0; i < str.size(); i++){
                if (str[i] >= ‘0‘ && str[i] <= ‘9‘)
                    str_num++;
                else if ((str[i] >= ‘a‘ && str[i] <= ‘z‘) || (str[i] >= ‘
 
A‘ && str[i] <= ‘Z‘))
                    str_letter++;
                else if (str[i] == ‘.‘)
                    str_dot++;
                else
                    str_other++;
            }
            if (str_other != 0)
                cout << "Your password is tai luan le.
 
" << endl;  // 這個可以很巧妙的實現太亂了這個選項，一般都會卡在這兒
            else if (str_num == 0)
                cout << "Your password needs shu zi." << endl;
            else if (str_letter == 0)
                cout << "Your password needs zi mu." << endl;
            else
                cout << "Your password is wan mei." << endl;
        }
    }
    return 0;
}

1081 檢查密碼 （15 分)