今天做修改的時候遇到個很奇怪的問題，參數是兩個對象，直接放到map中向消費者傳遞，方法用map接收，死活接收不到，問了下前輩說map中是多對象時接收容易出錯，推薦我傳遞JSON,照他說的把問題解決了，代碼發上來以後長個記性。

先看有問題的，請求：

public R updateChargeStandard(CaChargeStandardTemplate caChargeStandardTemplate){
        SysEmployeeInfo user = (SysEmployeeInfo) SecurityUtils.getSubject().getSession().getAttribute("user");
        Map
 
<String,Object> params = new HashMap<>();
        params.put("user",user);
        params.put("caChargeStandardTemplate",caChargeStandardTemplate);
       return chargeStandardService.updateChargeStandard(params);
    }

接收：

  public R updateChargeStandard(@RequestBody Map<String,Object> params){
        CaChargeStandardTemplate caChargeStandardTemplate 
 
= (CaChargeStandardTemplate)params.get("caChargeStandardTemplate");
        SysEmployeeInfo user = (SysEmployeeInfo)params.get("user");
        int i = chargeStandardService.updateChargeStandard(caChargeStandardTemplate,user);
        return  i > 0 ? R.ok("保存成功"):R.error("保存失敗");
    }

再看修改之後的

請求：

 public R updateChargeStandard(CaChargeStandardTemplate caChargeStandardTemplate){
        SysEmployeeInfo user = (SysEmployeeInfo) SecurityUtils.getSubject().getSession().getAttribute("user");
        Map<String,Object> params = new HashMap<>();
        String userStr = JSON.toJSONString(user); //對象轉String再放進map中
        String caChargeStandardTemplateStr = JSON.toJSONString(caChargeStandardTemplate);
        params.put("user",userStr);
        params.put("caChargeStandardTemplate",caChargeStandardTemplateStr);
       return chargeStandardService.updateChargeStandard(params);
    }

接收：

public R updateChargeStandard(@RequestBody Map<String,Object> params){
        String caChargeStandardTemplateStr = (String) params.get("caChargeStandardTemplate");//從map中取String
        CaChargeStandardTemplate caChargeStandardTemplate = JSON.parseObject(caChargeStandardTemplateStr,CaChargeStandardTemplate.class);//String轉對象
        String userStr = (String) params.get("user");//從map中取String
        SysEmployeeInfo user = JSON.parseObject(userStr,SysEmployeeInfo.class);//String轉對象
        int i = chargeStandardService.updateChargeStandard(caChargeStandardTemplate,user);
        return  i > 0 ? R.ok("保存成功"):R.error("保存失敗");
    }

end.

springCloud發送請求多對象參數傳遞問題