C語言實現自動發牌程式
阿新 • • 發佈:2020-04-23
C語言自動發牌程式,供大家參考,具體內容如下
一副撲克有52張牌,打橋牌時應將牌分給4個人。請設計一個程式完成自動發牌的工作。要求:黑桃用S (Spaces)表示,紅桃用H (Hearts)表示,方塊用D (Diamonds)表示,梅花用C (Clubs)表示。
分析:
要設定陣列表現撲克牌
要設定陣列表現玩家
要給撲克牌做特定標識,得到結果後玩家要知道自己手中黑桃有哪些、方塊有哪些
初步想法:
設定4個字元陣列儲存4種梅花牌,設定4個字元陣列表示4名玩家分配到的牌
每張牌隨機發給4名玩家,當玩家的持牌數達到13,不再分配給該名玩家牌
程式碼展示:
void mycode_13() { srand(unsigned(time(NULL))); /*全部牌*/ char S[13] = { '2','3','4','5','6','7','8','9','T','J','Q','K','A' }; char H[13] = { '2','A' }; char D[13] = { '2','A' }; char C[13] = { '2','A' }; /*4個玩家*/ char player1[13],player2[13],player3[13],player4[13]; int p1 = 0,p2 = 0,p3 = 0,p4 = 0; distribution(S,player1,player2,player3,player4,&p1,&p2,&p3,&p4); distribution(H,&p4); distribution(D,&p4); distribution(C,&p4); puts("執行結束"); for (int i = 0; i < 13; i++) printf("%c ",player1[i]); putchar('\n'); for (int i = 0; i < 13; i++) printf("%c ",player2[i]); putchar('\n'); for (int i = 0; i < 13; i++) printf("%c ",player3[i]); putchar('\n'); for (int i = 0; i < 13; i++) printf("%c ",player4[i]); } void distribution(char * S_H_D_C,char * player1,char * player2,char * player3,char * player4,int *p1,int *p2,int *p3,int *p4) { static int h = 1; int r; int a = *p1,b = *p2,c = *p3,d = *p4; for (int i = 0; i < 13; i++) { r = (rand() % 4) + 1; while ((r == 1 && (*p1) == 13) || (r == 2 && (*p2) == 13) || (r == 3 && (*p3) == 13) || (r == 4 && (*p4) == 13)) r = (rand() % 4) + 1; switch (r) { case 1: player1[(*p1)++] = S_H_D_C[i]; break; case 2: player2[(*p2)++] = S_H_D_C[i]; break; case 3: player3[(*p3)++] = S_H_D_C[i]; break; case 4: player4[(*p4)++] = S_H_D_C[i]; break; default: break; } } switch (h++) { case 1: printf("黑桃:\n"); break; case 2: printf("紅桃:\n"); break; case 3: printf("方塊:\n"); break; case 4: printf("梅花:\n"); break; } printf("Player1:"); for (int i = a; i < (*p1); i++) printf("%c ",player1[i]); putchar('\n'); printf("Player2:"); for (int i = b; i < (*p2); i++) printf("%c ",player2[i]); putchar('\n'); printf("Player3:"); for (int i = c; i < (*p3); i++) printf("%c ",player3[i]); putchar('\n'); printf("Player4:"); for (int i = d; i < (*p4); i++) printf("%c ",player4[i]); putchar('\n'); }
以下程式碼保證了當某個人得到13張牌後不在得牌
r = (rand() % 4) + 1; while ((r == 1 && (*p1) == 13) || (r == 2 && (*p2) == 13) || (r == 3 && (*p3) == 13) || (r == 4 && (*p4) == 13)) r = (rand() % 4) + 1;
以上就是本文的全部內容,希望對大家的學習有所幫助,也希望大家多多支援我們。