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C語言實現自動發牌程式

C語言自動發牌程式,供大家參考,具體內容如下

一副撲克有52張牌,打橋牌時應將牌分給4個人。請設計一個程式完成自動發牌的工作。要求:黑桃用S (Spaces)表示,紅桃用H (Hearts)表示,方塊用D (Diamonds)表示,梅花用C (Clubs)表示。

分析:

要設定陣列表現撲克牌
要設定陣列表現玩家
要給撲克牌做特定標識,得到結果後玩家要知道自己手中黑桃有哪些、方塊有哪些

初步想法:

設定4個字元陣列儲存4種梅花牌,設定4個字元陣列表示4名玩家分配到的牌
每張牌隨機發給4名玩家,當玩家的持牌數達到13,不再分配給該名玩家牌

程式碼展示:

void mycode_13()
{
 srand(unsigned(time(NULL)));
 /*全部牌*/
 char S[13] = { '2','3','4','5','6','7','8','9','T','J','Q','K','A' };
 char H[13] = { '2','A' };
 char D[13] = { '2','A' };
 char C[13] = { '2','A' };

 /*4個玩家*/
 char player1[13],player2[13],player3[13],player4[13];
 int p1 = 0,p2 = 0,p3 = 0,p4 = 0;

 distribution(S,player1,player2,player3,player4,&p1,&p2,&p3,&p4);
 distribution(H,&p4);
 distribution(D,&p4);
 distribution(C,&p4);

 puts("執行結束");

 for (int i = 0; i < 13; i++)
 printf("%c ",player1[i]);
 putchar('\n');
 for (int i = 0; i < 13; i++)
 printf("%c ",player2[i]);
 putchar('\n');
 for (int i = 0; i < 13; i++)
 printf("%c ",player3[i]);
 putchar('\n');
 for (int i = 0; i < 13; i++)
 printf("%c ",player4[i]);
}

void distribution(char * S_H_D_C,char * player1,char * player2,char * player3,char * player4,int *p1,int *p2,int *p3,int *p4)
{
 static int h = 1;
 int r;
 int a = *p1,b = *p2,c = *p3,d = *p4;

 for (int i = 0; i < 13; i++)
 {
 r = (rand() % 4) + 1;
 while ((r == 1 && (*p1) == 13) || (r == 2 && (*p2) == 13) || (r == 3 && (*p3) == 13) || (r == 4 && (*p4) == 13))
  r = (rand() % 4) + 1;
 
 switch (r)
 {
 case 1:
  player1[(*p1)++] = S_H_D_C[i];
  break;
 case 2:
  player2[(*p2)++] = S_H_D_C[i];
  break;
 case 3:
  player3[(*p3)++] = S_H_D_C[i];
  break;
 case 4:
  player4[(*p4)++] = S_H_D_C[i];
  break;
 default:
  break;
 }
 }
 
 switch (h++)
 {
 case 1:
  printf("黑桃:\n");
  break;
 case 2:
  printf("紅桃:\n");
  break;
 case 3:
  printf("方塊:\n");
  break;
 case 4:
  printf("梅花:\n");
  break;
 }
 
 printf("Player1:");
 for (int i = a; i < (*p1); i++)
  printf("%c ",player1[i]);

 putchar('\n');
 
 printf("Player2:");
 for (int i = b; i < (*p2); i++)
  printf("%c ",player2[i]);
 
 putchar('\n');
 printf("Player3:");
 for (int i = c; i < (*p3); i++)
  printf("%c ",player3[i]);
 
 putchar('\n');
 
 printf("Player4:");
 for (int i = d; i < (*p4); i++)
  printf("%c ",player4[i]);

 putchar('\n');
}

以下程式碼保證了當某個人得到13張牌後不在得牌

r = (rand() % 4) + 1;
 while ((r == 1 && (*p1) == 13) || (r == 2 && (*p2) == 13) || (r == 3 && (*p3) == 13) || (r == 4 && (*p4) == 13))
  r = (rand() % 4) + 1;

以上就是本文的全部內容,希望對大家的學習有所幫助,也希望大家多多支援我們。