技術標籤：C語言

有兩個磁碟檔案A和B，各自存放一行字母，今要求把這兩個檔案中的資訊合併（按字母順序排序），輸出到一個新檔案C中去

#include <stdio.h>
#include <stdlib.h>

/* run this program using the console pauser or add your own getch, system("pause") or input loop */

void file(char f[])
{
	FILE *fp;
	char ch,file[10];
	printf("請輸入檔案的名字："
 
);
	scanf("%s",file);
	getchar();
	if((fp=fopen(file,"wb"))==NULL)
	{
		printf("can not open file\n");
		exit(0); 
	}
	printf("請輸入一個準備儲存到磁碟的字串（以#結束）：");
	ch=getchar();
	while(ch!='#')
	{
		fputc(ch,fp);
		putchar(ch);
		ch=getchar();
	}
	fclose(fp);
 } 
 
 int main
 
()
 {
 	FILE *fp1,*fp2,*fp3;
 	char ch,t,filename1[10],filename2[10],filename3[10],c[200];
 	int a,b,i,j,n=0;
 	printf("Please enter the name of file:");
 	scanf("%s",filename1);
 	printf("Now is the %s file!\n",filename1);
 	file(filename1);
 	printf("\n");
 	printf
 
("Please enter the name of file:");
 	scanf("%s",filename2);
 	printf("Now is the %s file!\n",filename2);
 	file(filename2);
 	if((fp1=fopen(filename1,"rb"))==NULL)
	{
		printf("can not open file\n");
		exit(0); 
	}
	printf("%s contest are:",filename1);
 	for(i=0;(ch=fgetc(fp1))!=EOF;i++)
    {
	  c[i]=ch;
      putchar(c[i]);
      n++;
    }
    fclose(fp1);
    i=n;
    if((fp2=fopen(filename2,"rb"))==NULL)
	{
		printf("can not open file\n");
		exit(0); 
	}
	printf("\n");
    printf("%s contest are:",filename2);
    for(;(ch=fgetc(fp2))!=EOF;i++)
    {
    	c[i]=ch;
      putchar(c[i]);
	}
	fclose(fp2);
	n=i;
	//排序
	for(i=0;i<n;i++)
	{
		for(j=i+1;j<n;j++)
		{
			a=c[i];
			b=c[j];
			if(a>b)
			{
				t=c[i];
				c[i]=c[j];
				c[j]=t;
			}
			
		}
	}
	printf("\n"); 
 	printf("Please enter the name of file:");
 	scanf("%s",filename3);
 	getchar();
 	printf("Now is the %s file!\n",filename3);
 	 if((fp3=fopen(filename3,"wb"))==NULL)
	{
		printf("can not open file\n");
		exit(0); 
	}
	
	for(i=0;i<n;i++)
	{
		putc(c[i],fp3);
		putchar(c[i]);
	}
 	fclose(fp3);
 	return 0;
 }

這是我自己在寫這道題時的做法，我知道有很多的不足，希望可以幫到你一點，如果你有更好的辦法，可以指出來哦！