技術標籤：Codeup新家

注意：
判斷A[2]的時候一定要通過個數來判斷否則91分如圖

#include<cstdio>
#include<cmath>
void count(int number, int *a);

int main(){
	int i = 0;
	int nums = 0;
	int number = 0;
	int A[7] = {0};
	double temp = 0;
	while(scanf("%d", &nums) != EOF){
		for(i = 0; i < nums; i++){
			scanf
 
("%d", &number);
			count(number, A);
		}
		temp = A[4] / (A[6] * 1.0);
		//A[1]
		if(A[1] != 0){
			printf("%d ", A[1]);
		}else{
			printf("N ");
		}
		//A[2]
		if(A[0] != 0){
			printf("%d ", A[2]);
		}else{
			printf("N ");
		}
		//A[3]
		if(A[3] != 0){
			printf
 
("%d ", A[3]);
		}else{
			printf("N ");
		} 
		//A[4]
		if(A[6] != 0){
			printf("%.1f ", temp);
		}else{
			printf("N ");
		}
		//A[5]
		if(A[5] != 0){
			printf("%d", A[5]);
		}else{
			printf("N");
		}
		//清零 
		for(i = 0; i < 7; i++){
			A[i]
 
 = 0;
		}
	}
	return 0;
}
void count(int number, int *a){
	 if(number % 10 == 0){
	 	a[1] += number;
	 }else if(number % 5 == 1){
	 	a[0]++;
	 	a[2] = a[2] + pow(-1, a[0]-1) * number;
	 }else if(number % 5 == 2){
	 	a[3]++;
	 }else if(number % 5 == 3){
	 	a[6]++; 
		a[4] = a[4] + number;
	 }else if(number % 5 == 4){
	 	
	 	if(number > a[5]){
			a[5] = number;
		}
	 }
}