There were 5 failed launches in a row, each lasting less than 300 seconds. Giving up
問題：mycat無法執行，Navicat無法連線mycat
在啟動mycat是後顯示的是mycat正在執行，但是Navicat還是無法連線，繼而檢視mycat的狀態，發現mycat的服務並不在執行。
[[email protected] bin]# ./mycat start
Starting Mycat-server...
./mycat status
[[email protected] bin]# ./mycat status
Mycat-server is not running.
檢視日誌：
解決：
原因：這是因為wrapper註冊的java服務起動超時，在conf下往wrapper.conf檔案新增或者修改以下內容。
#設定超時時間
wrapper.startup.timeout=7200相關推薦
There were 5 failed launches in a row, each lasting less than 300 seconds. Giving up
技術標籤：mycat連線異常mysql 問題：mycat無法執行，Navicat無法連線mycat 在啟動mycat是後顯示的是mycat正在執行，但是Navicat還是無法連線，繼而檢視mycat的狀態，發現mycat的服務並不在執行。
[LeetCode] 1292. Maximum Side Length of a Square with Sum Less than or Equal to Threshold 元素和小於等於閾值的正方形的最大邊長
Given a m x n matrix mat and an integer threshold, return the maximum side-length of a square with a sum less than or equal to threshold or return 0 if there is no such square.
MySQL主從複製中的問題（Coordinator stopped beacause there were errors in the workers......）
1、show slave status \\G 顯示如下報錯資訊： Coordinator stopped because there were error(s) in the worker(s). The most recent failure being: Worker 1 failed executing transaction ...
There are m towns in a straight line, with a road joining each pair of consecutive towns.
There are m towns in a straight line, with a road joining each pair of consecutive towns. Legends say that an ordinary person in one of these towns will become a hero by completing a sequence of n que
C#基礎學習C# 8.0 In a Nut Shell
Field 其實就是變數，但是英文裡面是field，欄位，域名。為啥要這麼取名是因為面向物件程式設計，發明類，事兒多，什麼防止變數被修改什麼的，所以發明了屬性property
selenium開啟瀏覽器底層實現原理中的異常4(Failed to establish a new connection: [WinError 10061] 由於目標計算機積 極拒絕，無法連線)
程式碼： #coding=utf-8 importrequests importjson url=‘http://127.0.0.1:4444/wd/hub/session‘ data=json.dumps({
LeetCode | 0700. Search in a Binary Search Tree二叉搜尋樹中的搜尋【Python】
LeetCode 0700. Search in a Binary Search Tree二叉搜尋樹中的搜尋【Easy】【Python】【二叉樹】
CF914F Substrings in a String
題面 英文題面 題意：給一個串\\(S\\)，有\\(q\\)次操作： 1 i c表示將\\(i\\)位置的字元修改為\\(c\\)；2 l r t表示求\\(s_{l},s_{l+1},\\cdots s_r\\)中\\(t\\)串的出現次數。
【LeetCode】【Math】X of a Kind in a Deck of Cards
題目： 在一副紙牌中，每張紙牌上都有一個整數。 當且僅當您可以選擇X> = 2並可以將整個卡片組分成1組或多組卡片時，才返回true，其中：
AtCoder Beginner Contest 173 D - Chat in a Circle
D - Chat in a Circle Time Limit: 2 sec / Memory Limit: 1024 MB Score:400400points Problem Statement Quickly after finishing the tutorial of the online gameATChat, you have decided to visit a partic
Failed to configure a DataSource: 'url' attribute is not specified and no embedded datasource could be configured.
問題： 問題分析及解決方案 問題原因: Mybatis沒有找到合適的載入類,其實是大部分spring - datasource - url沒有載入成功,分析原因如下所示.
CF914F Substrings in a String bitset的應用 Shift -And
給你一個字串s，共有q次操作，每個都是下面兩種形式的一種。 1i c：這個操作表示將字串s的第i項變為字元c
914. X of a Kind in a Deck of Cards
In a deck of cards, each card has an integer written on it. Returntrueif and only if you can chooseX >= 2such thatit is possible to split the entire deckinto 1 or more groups of cards, where:
1252. Cells with Odd Values in a Matrix
問題： 給定矩陣尺寸n*m，矩陣初始化為全為0， 和操作物件行列陣列，indices[i] = [ri, ci]
[LeetCode] 329. Longest Increasing Path in a Matrix
Given an integer matrix, find the length of the longest increasing path. From each cell, you can either move to four directions: left, right, up or down. You may NOT move diagonally or move outside of
[USACO12MAR]Cows in a Skyscraper G
題目連結: P3052 [USACO12MAR]Cows in a Skyscraper G 題目大意: 給出n個物品，體積為w[i]，現把其分成若干組，要求每組總體積<=W，問最小分組。(n<=18)
(單調棧)Largest Rectangle in a Histogram
之前寫hdu1505的時候居然用錯誤的演算法給水過去了（實際上那個題目從高度1開始列舉，我那個記錄每個元素id的做法好像也行）
438. Find All Anagrams in a String 查詢字串中的所有Anagrams
Given a stringsand anon-emptystringp, find all the start indices ofp\'s anagrams ins. Strings consists of lowercase English letters only and the length of both stringssandpwill not be larger than 20,1
Django 報錯 Refused to display 'http://127.0.0.1:8000/ in a frame because it set 'X-Frame-Option
如圖： 檢視程式碼： iframe 連結的地址src = \'/account/my-image/\'的body是空的 檢視setting配置，如下：
SPOJ PT07Z, Longest path in a tree 樹的直徑
SPOJ PT07Z, Longest path in a tree #include <iostream> #include <vector> #include <algorithm>