演算法之數學驗證尼科徹斯定理
阿新 • • 發佈:2022-03-05
分析和思路:
接受輸入資料後,從1開始遍歷,找到連續相加和的連續奇數即可。back變數的設定有些技巧。
1 #include <iostream> 2 #include "iostream" 3 #include "string" 4 5 using namespace std; 6 7 int main() 8 { 9 10 int number = 0; 11 while (cin >> number) 12 { 13 int b[100] = { 0 }; 14 int a = 1; 15 16主要為了自己學習while (1) 17 { 18 int back = a; 19 int sum = 0; 20 for (int i = 0; i < number; i++) 21 { 22 b[i] = back; 23 back = back + 2; 24 } 25 for (int i = 0; i < number; i++) 26 {27 sum += b[i]; 28 } 29 if (sum == number * number*number) 30 { 31 // cout << "yes"; 32 for (int i = 0; i < number-1; i++) 33 { 34 cout << b[i] << "+"; 35 36} 37 cout << b[number - 1]<<endl; 38 break; 39 } 40 else 41 { 42 a = a + 2; 43 sum = 0; 44 continue; 45 } 46 } 47 } 48 49 return 0; 50 }