0967. Numbers With Same Consecutive Differences (M)
阿新 • • 發佈:2020-08-19
Numbers With Same Consecutive Differences (M)
題目
Return all non-negative integers of length N
such that the absolute difference between every two consecutive digits is K
.
Note that every number in the answer must not have leading zeros except for the number 0
itself. For example, 01
has one leading zero and is invalid, but 0
You may return the answer in any order.
Example 1:
Input: N = 3, K = 7
Output: [181,292,707,818,929]
Explanation: Note that 070 is not a valid number, because it has leading zeroes.
Example 2:
Input: N = 2, K = 1
Output: [10,12,21,23,32,34,43,45,54,56,65,67,76,78,87,89,98]
Note:
1 <= N <= 9
0 <= K <= 9
題意
求所有的N位數,使得其中每一個數中的每相鄰兩個位的數字之差為K。
思路
用回溯法去生成每一個這樣的N位數。需要注意的坑是N=1時要考慮0,以及K=0時注意剪枝。
程式碼實現
Java
class Solution { public int[] numsSameConsecDiff(int N, int K) { List<Integer> list = new ArrayList<>(); for (int i = N == 1 ? 0 : 1; i < 10; i++) { dfs(0, i, 1, N, K, list); } int[] ans = new int[list.size()]; int i = 0; for (int num : list) { ans[i++] = num; } return ans; } private void dfs(int num, int digit, int index, int N, int K, List<Integer> list) { if (digit < 0 || digit > 9) { return; } num = num * 10 + digit; if (index == N) { list.add(num); return; } dfs(num, digit + K, index + 1, N, K, list); if (K > 0) { dfs(num, digit - K, index + 1, N, K, list); } } }