相同的雪花 Hash
阿新 • • 發佈:2017-05-20
難度 輸入 air measure his else describe tmp clr
相同的雪花
時間限制:1000 ms | 內存限制:65535 KB 難度:4- 描述
- You may have heard that no two snowflakes are alike. Your task is to write a program to determine whether this is really true. Your program will read information about a collection of snowflakes, and search for a pair that may be identical. Each snowflake has six arms. For each snowflake, your program will be provided with a measurement of the length of each of the six arms. Any pair of snowflakes which have the same lengths of corresponding arms should be flagged by your program as possibly identical.
- 輸入
- The first line of the input will contain a single interger T(0<T<10),the number of the test cases.
The first line of every test case will contain a single integer n, 0 < n ≤ 100000, the number of snowflakes to follow. This will be followed by n lines, each describing a snowflake. Each snowflake will be described by a line containing six integers (each integer is at least 0 and less than 10000000), the lengths of the arms of the snow ake. The lengths of the arms will be given in order around the snowflake (either clockwise or counterclockwise), but they may begin with any of the six arms. For example, the same snowflake could be described as 1 2 3 4 5 6 or 4 3 2 1 6 5. - 輸出
- For each test case,if all of the snowflakes are distinct, your program should print the message:
No two snowflakes are alike.
If there is a pair of possibly identical snow akes, your program should print the message:
Twin snowflakes found. - 樣例輸入
-
1 2 1 2 3 4 5 6 4 3 2 1 6 5
- 樣例輸出
-
Twin snowflakes found.
註意hash表大小#include<iostream> #include<cstdio> #include<cmath> #include<cstring> #include<sstream> #include<algorithm> #include<queue> #include<deque> #include<iomanip> #include<vector> #include<cmath> #include<map> #include<stack> #include<set> #include<fstream> #include<memory> #include<list> #include<string> using namespace std; typedef long long LL; typedef unsigned long long ULL; #define MAXN 100001 #define INF 1000000009 #define eps 0.00000001 /* 尋找是否有兩片相同的雪花 雪花的邊可能從任意一邊 開始! Hash 雪花總邊長 */ typedef struct Hashnode { int a[6]; struct Hashnode* next; }*List; typedef struct HashT { List* L; }*HashTable; int NextPrime(int n) { int i; for (int tmp = n;; tmp++) { for (i = 2; i*i <= tmp; i++) { if (tmp%i == 0) break; } if (i*i > tmp) return i; } } HashTable Init(int n) { HashTable H = (HashTable)malloc(sizeof(HashT)); H->L = (List*)malloc(sizeof(List)*MAXN); for (int i = 0; i < MAXN; i++) { H->L[i] = (List)malloc(sizeof(Hashnode)); memset(H->L[i]->a, 0, sizeof(H->L[i]->a)); H->L[i]->next = NULL; } return H; } void Free(HashTable H) { for (int i = 0; i < MAXN; i++) free(H->L[i]); free(H->L); free(H); } int Hash(int sum, int h) { return sum%h; } List Find(int a[6], int sum, HashTable H) { List p = H->L[Hash(sum, MAXN)]; List l = p->next; int i; while (l != NULL) { for (int j = 0; j < 6; j++) { if (l->a[j] == a[0]) { for (i = 1; i < 6; i++) { if (l->a[(j + i) % 6] != a[i]) break; } if (i == 6) return l; for (i = 1; i < 6; i++) { if (l->a[(j - i + 6) % 6] != a[i]) break; } if (i == 6) return l; } } l = l->next; } return NULL; } bool Insert(int a[6], int sum, HashTable H) { List L = H->L[Hash(sum, MAXN)]; List p = Find(a, sum, H); if (p == NULL) { List tmp = (List)malloc(sizeof(Hashnode)); for (int i = 0; i < 6; i++) tmp->a[i] = a[i]; tmp->next = L->next; L->next = tmp; return true; } return false; } int main() { int T, n, tmp[6]; bool f; scanf("%d", &T); while (T--) { scanf("%d", &n); f = false; HashTable H = Init(n); for (int i = 0; i < n; i++) { int sum = 0; for (int j = 0; j < 6; j++) { scanf("%d", &tmp[j]); sum += tmp[j]; } if (!f && !Insert(tmp, sum, H)) f = true; } if (f) printf("Twin snowflakes found.\n"); else printf("No two snowflakes are alike.\n"); Free(H); } return 0; }
相同的雪花 Hash