CF839 C 樹形DP 期望
阿新 • • 發佈:2017-08-29
push_back spa .cpp ack 出發 com name tps ems
給一顆樹,求從根出發路徑長度的期望是多少。
樹形DP 要想清楚期望的計算
/** @Date : 2017-08-12 23:09:41 * @FileName: C.cpp * @Platform: Windows * @Author : Lweleth ([email protected]) * @Link : https://github.com/ * @Version : $Id$ */ #include <bits/stdc++.h> #define LL long long #define PII pair<int ,int> #define MP(x, y) make_pair((x),(y)) #define fi first #define se second #define PB(x) push_back((x)) #define MMG(x) memset((x), -1,sizeof(x)) #define MMF(x) memset((x),0,sizeof(x)) #define MMI(x) memset((x), INF, sizeof(x)) using namespace std; const int INF = 0x3f3f3f3f; const int N = 1e5+20; const double eps = 1e-6; vector<int>edg[N]; int vis[N]; double f[N]; double dfs(int x, int pre) { int flag = 0; for(auto i: edg[x]) { if(i == pre) continue; flag++; dfs(i, x); f[x] += f[i]; } if(flag) f[x] = 1.0*f[x]/flag + 1; } int main() { int n; while(cin >> n) { MMF(vis); for(int i = 0; i <= n; i++) edg[i].clear(); for(int i = 0; i < n - 1; i++) { int x, y; scanf("%d%d", &x, &y); edg[x].PB(y); edg[y].PB(x); } dfs(1, -1); //cout << ans << " "<< cnt << endl; //printf("%.10lf\n", (1.0000000*ans/cnt)); printf("%.10lf\n", f[1]); } return 0; }
CF839 C 樹形DP 期望