1. 程式人生 > >BZOJ 1922 大陸爭霸

BZOJ 1922 大陸爭霸

class max define span pop tin val turn logs

有點迷,spfa好像不好寫,必須dijkstra

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<queue>
#define maxv 3050
#define maxe 70050
using namespace std;
int n,m,x,y,z,l,cnt[maxv],con[maxv][maxv],d1[maxv],d2[maxv],g[maxv],nume=1;
struct pnt
{
    int v,val;
    pnt (
int v,int val):v(v),val(val) {} pnt () {} friend bool operator < (const pnt &x,const pnt &y) { return x.val>y.val; } }p[maxv]; priority_queue <pnt> q; bool vis[maxv]; struct edge { int v,w,nxt; }e[maxe]; void addedge(int u,int v,int w) { e[++nume].v=v;e[nume].w=w; e[nume].nxt
=g[u];g[u]=nume; } void dijkstra() { q.push(pnt(1,0)); for (int i=2;i<=n;i++) d1[i]=1000000000; while (!q.empty()) { pnt head=q.top();q.pop(); if (vis[head.v]) continue;vis[head.v]=true; for (int i=g[head.v];i;i=e[i].nxt) { int v=e[i].v;
if (d1[v]>max(d1[head.v],d2[head.v])+e[i].w) { d1[v]=max(d1[head.v],d2[head.v])+e[i].w; if (!cnt[v]) q.push(pnt(v,max(d1[v],d2[v]))); } } for (int i=1;i<=con[head.v][0];i++) { int v=con[head.v][i]; cnt[v]--;d2[v]=max(d2[v],max(d1[head.v],d2[head.v])); if (!cnt[v]) q.push(pnt(v,max(d1[v],d2[v]))); } } } int main() { scanf("%d%d",&n,&m); for (int i=1;i<=m;i++) { scanf("%d%d%d",&x,&y,&z); if (x!=y) addedge(x,y,z); } for (int i=1;i<=n;i++) { scanf("%d",&cnt[i]); for (int j=1;j<=cnt[i];j++) { scanf("%d",&x); con[x][++con[x][0]]=i; } } dijkstra(); printf("%d\n",max(d1[n],d2[n])); return 0; }

BZOJ 1922 大陸爭霸