POJ-1659 Frogs' Neighborhood---Havel-Hakimi定理
阿新 • • 發佈:2018-04-08
poj pri HR tdi () pro 建圖 turn blog
題目鏈接:
https://vjudge.net/problem/POJ-1659
題目大意:
給定度數列,判斷是否可以建圖
思路:
Havel-Hakimi定理
1 #include<iostream> 2 #include<cstdio> 3 #include<cstring> 4 #include<algorithm> 5 #include<cmath> 6 #include<queue> 7 #include<stack> 8 #include<map> 9 #include<set> 10 #include<sstream> 11 #include<functional> 12 using namespace std; 13 typedef long long ll; 14 const int maxn = 1e2 + 10; 15 const int INF = 1e9 + 7; 16 int T, n, m, cases; 17 int Map[maxn][maxn]; 18 struct node 19 { 20 int x, id; 21 bool operator<(const node & a)const22 { 23 return x > a.x; 24 } 25 }a[maxn]; 26 27 int main() 28 { 29 cin >> T; 30 while(T--) 31 { 32 cin >> n; 33 for(int i = 0; i < n; i++) 34 { 35 cin >> a[i].x; 36 a[i].id = i; 37 } 38 memset(Map, 0, sizeof(Map)); 39 bool flag = 1; 40 for(int i = 0; i < n; i++) 41 { 42 sort(a + i, a + n); 43 if(a[i].x >= n - i) 44 { 45 flag = 0; 46 break; 47 } 48 for(int j = 1 + i; j <= a[i].x + i; j++) 49 { 50 a[j].x--; 51 if(a[j].x < 0)flag = 0; 52 Map[a[i].id][a[j].id] = Map[a[j].id][a[i].id] = 1; 53 } 54 } 55 if(flag) 56 { 57 puts("YES"); 58 for(int i = 0; i < n; i++) 59 { 60 printf("%d", Map[i][0]); 61 for(int j = 1; j < n; j++) 62 { 63 printf(" %d", Map[i][j]); 64 } 65 puts(""); 66 } 67 } 68 else puts("NO"); 69 if(T)cout<<endl; 70 } 71 return 0; 72 }
POJ-1659 Frogs' Neighborhood---Havel-Hakimi定理