1. 程式人生 > >BZOJ3112 [Zjoi2013]防守戰線 【單純形】

BZOJ3112 [Zjoi2013]防守戰線 【單純形】

def IT == AR 誌願 cti rep 神題 招募

題目鏈接

BZOJ3112

題解

同誌願者招募
費用流神題
單純形裸題
\(BZOJ\)可過
洛谷被卡。。

#include<algorithm>
#include<iostream>
#include<cstring>
#include<cstdlib>
#include<cstdio>
#include<ctime>
#include<cmath>
#include<map>
#define Redge(u) for (int k = h[u],to; k; k = ed[k].nxt)
#define REP(i,n) for (int i = 1; i <= (n); i++)
#define mp(a,b) make_pair<int,int>(a,b) #define cls(s) memset(s,0,sizeof(s)) #define cp pair<int,int> #define LL long long int using namespace std; const int maxn = 1005,maxm = 10005; const double eps = 1e-8,INF = 1e15; inline int read(){ int out = 0,flag = 1; char c = getchar(); while
(c < 48 || c > 57){if (c == '-') flag = -1; c = getchar();} while (c >= 48 && c <= 57){out = (out << 3) + (out << 1) + c - 48; c = getchar();} return out * flag; } int n,m; double a[maxm][maxn]; void Pivot(int l,int e){ double t = a[l][e]; a[l][e] = 1
; for (int j = 0; j <= n; j++) a[l][j] /= t; for (int i = 0; i <= m; i++) if (i != l && fabs(a[i][e]) > eps){ t = a[i][e]; a[i][e] = 0; for (int j = 0; j <= n; j++) a[i][j] -= a[l][j] * t; } } void init(){ while (true){ int l = 0,e = 0; for (int i = 1; i <= m; i++) if (a[i][0] < -eps && (!l || (rand() & 1))) l = i; if (!l) break; for (int j = 1; j <= n; j++) if (a[l][j] < -eps && (!e || (rand() & 1))) e = j; Pivot(l,e); } } void simplex(){ while (true){ int l = 0,e = 0; double mn = INF; for (int j = 1; j <= n; j++) if (a[0][j] > eps){e = j; break;} if (!e) break; for (int i = 1; i <= m; i++) if (a[i][e] > eps && a[i][0] / a[i][e] < mn) mn= a[i][0] / a[i][e],l = i; Pivot(l,e); } } int main(){ srand(time(NULL)); n = read(); m = read(); int L,R; REP(j,n) a[0][j] = -read(); REP(i,m){ L = read(); R = read(); for (int j = L; j <= R; j++) a[i][j] = -1; a[i][0] = -read(); } init(); simplex(); printf("%lld\n",(LL)(a[0][0] + 0.5)); return 0; }

BZOJ3112 [Zjoi2013]防守戰線 【單純形】