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Problem Description Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the max sum in this sequence is 6 + (-1) + 5 + 4 = 14. Input The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line starts with a number N(1<=N<=100000), then N integers followed(all the integers are between -1000 and 1000). Output For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line contains three integers, the Max Sum in the sequence, the start position of the sub-sequence, the end position of the sub-sequence. If there are more than one result, output the first one. Output a blank line between two cases. Code

#include<stdio.h>
 
int main()
{
    int t,n,i,j;
    int a;
    int sum,maxsum,start,end,temp;
    scanf("%d",&t);
    i=1;
    while(i<=t)
    {
        scanf("%d",&n);
        sum=0,maxsum=-1001,start=0,end=0,temp=1;
        for(j=0;j<n;j++)
        {
            scanf("%d",&a);
            sum += a;
            if
 
(sum>maxsum)
            {
                maxsum=sum;
                start=temp;
                end=j+1;
            }
            if(sum<0)
            {
                sum=0;
                temp=j+2;
            }
        }
        printf("Case %d:\n",i);
        printf("%d %d %d\n",maxsum,
 
start,end);
        if(i!=t)
            printf("\n");
        i++;
    }
    return 0;
}

Max Sum