ACM-ICPC 2018 南京賽區網絡預賽
阿新 • • 發佈：2018-09-15
pan def all ron sta || pop family show 
A An Olympian Math Problem
#include <bits/stdc++.h> using namespace std; typedef long long ll; ll T,n; int main(){ scanf("%lld",&T); while(T--){ scanf("%lld",&n); printf("%lld\n",n-1); } }View Code
B The writing on the wall
C GDY
D Jerome‘s House
E AC Challenge
#include <bits/stdc++.h> using namespace std; long long a[25],b[25]; long long dis[2000005]; int vis[2000005]; int pre[25]; int sta[25]; int main() { memset(sta,0,sizeof(sta)); memset(dis,0,sizeof(dis)); memset(vis,0,sizeof(vis)); int n; scanf(View Code"%d",&n); for(int i = 0;i < n;++i){ scanf("%lld%lld%d",&a[i],&b[i],&pre[i]); int p; for(int j = 0;j < pre[i];++j){ scanf("%d",&p); sta[i] |= (1<<(p-1)); }//cout << sta[i] << endl; } int now = 0; queue<int> Q; while(!Q.empty()) Q.pop(); Q.push(0); while(!Q.empty()){ now = Q.front(); Q.pop(); vis[now] = 0; for(int i = 0;i < n;++i){ if((sta[i] & now) == sta[i] && ((1<<i) & now) == 0){ int nxt = now | (1<<i); int cnt = 0; for(int j = 0;j < n;++j) if((1<<j)&nxt) cnt++; if(dis[nxt] < dis[now] + cnt*a[i] + b[i]){ dis[nxt] = dis[now] + cnt*a[i] + b[i]; if(!vis[nxt]) Q.push(nxt),vis[nxt] = 1; } } } } int up = (1<<n); long long ans = 0; for(int i = 0;i < up;++i) ans = max(ans,dis[i]); cout << ans << endl; return 0; }
F An Easy Problem On The Trees
G Lpl and Energy-saving Lamps
H Set
I Skr
J Sum
#include <bits/stdc++.h> using namespace std; #define N 20000006 int prime[N],tag[N]; int get_prime(int n){ int tot = 0; for(int i = 2;i <= n;++i){ if(!tag[i]) prime[tot++] = i; for(int j = 0;j < tot && 1LL * prime[j] * i <= n;++j){ tag[i * prime[j]] = 1; if(i % prime[j] == 0) break; } } return tot; } int cnt; int ct; int dfs(int now,int n){ ct++; if(n == 0) return 0; if(now == cnt || prime[now] > n) return 1; if(prime[now]*prime[now] > n){ int tmp = (upper_bound(prime,prime+cnt,n)-prime)-now; return tmp*2+1; } int ans = 0; ans += dfs(now+1,n/(1LL*prime[now]*prime[now])); ans += 2*dfs(now+1,n/prime[now]); ans += dfs(now+1,n); return ans; } int main() { cnt = get_prime(20000000); int T; scanf("%d",&T); while(T--){ int n; scanf("%d",&n); ct = 0; printf("%d\n",dfs(0,n)); //cout << ct << endl; } return 0; }View Code
K The Great Nim Game
L Magical Girl Haze
#include <bits/stdc++.h> using namespace std; #define M 200005 #define N 100005 int head[N]; bool vis[N][11]; long long dis[N][11]; int cnt; struct Edge{ int to,next,l; }edge[M<<1]; void ad(int u,int v,int c){ edge[cnt].to = v,edge[cnt].next = head[u],edge[cnt].l = c,head[u] = cnt++; } struct Node{ int p,tim; long long dis; bool operator < (const Node &a)const{ return dis > a.dis; } }; priority_queue<Node> Q; int main() { int T; scanf("%d",&T); while(T--){ cnt = 0; memset(head,-1,sizeof(head)); memset(dis,0x3f,sizeof(dis)); memset(vis,0,sizeof(vis)); int n,m,k; int u,v,c; scanf("%d%d%d",&n,&m,&k); for(int i = 1;i <= m;++i){ scanf("%d%d%d",&u,&v,&c); ad(u,v,c); } dis[1][0] = 0; while(!Q.empty()) Q.pop(); Node nd; nd.p = 1,nd.tim = 0,nd.dis = dis[1][0]; Q.push(nd); long long l; while(!Q.empty()){ nd = Q.top(); Q.pop(); int u = nd.p,tim = nd.tim; if (vis[u][tim]) continue; vis[u][tim] = 1; for(int i = head[u];i != -1;i = edge[i].next){ v = edge[i].to; l = edge[i].l; if(tim + 1 <= k){ if(!vis[v][tim+1] && dis[v][tim+1] > dis[u][tim]){ dis[v][tim+1] = dis[u][tim]; nd.p = v,nd.tim = tim+1,nd.dis = dis[v][tim+1]; Q.push(nd); } } if(!vis[v][tim] && dis[v][tim] > dis[u][tim] + l){ dis[v][tim] = dis[u][tim] + l; nd.p = v,nd.tim = tim,nd.dis = dis[v][tim]; Q.push(nd); } } } long long ans = 0x3f3f3f3f3f3f3f3f; for(int i = 0;i <= k;++i) ans = min(ans,dis[n][i]); cout << ans << endl; } return 0; }View Code
ACM-ICPC 2018 南京賽區網絡預賽