any each 字符 test case miss cal ref con inpu

（置頂，復習）A + B Again

鏈接：http://acm.hdu.edu.cn/showproblem.php?pid=2057

Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 35905 Accepted Submission(s): 14614

Problem Description There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

Input The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.

Output For each test case,print the sum of A and B in hexadecimal in one line.

Sample Input +A -A +1A 12 1A -9 -1A -12 1A -AA

Sample Output 0 2C 11 -2C -90

Author linle 註： 此題就是利用Long.parseLong()和Long.toHexString（）的 replaceAll("\\+","")，是去除其中的‘+’，因為進制計算不支持帶“+”的某一進制的數字字符串，‘-’可以，同時還需要判斷正數負數，從而利用Long.toHexString（）。

Java代碼：

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner inScanner = new Scanner(System.in);
        while(inScanner.hasNext()) {
            long l = Long.parseLong(inScanner.next().replaceAll("\\+", ""),16)
                    + Long.parseLong(inScanner.next().replaceAll("\\+", ""),16);
            if(l<0) {
                System.out.println("-" + Long.toHexString(-l).toUpperCase());
            }
            else {
                System.out.println(Long.toHexString(l).toUpperCase());
            }
        }
    }
}

(JAVA對進制的運算)A + B Again hdu2057 要復習