AGC027 A - Candy Distribution Again
阿新 • • 發佈:2018-09-26
string etc 題目 contest cstring getchar \n clu while
目錄
- 題目鏈接
- 題解
- 代碼
題目鏈接
AGC027 A - Candy Distribution Again
題解
貪心即可
代碼
#include<cstdio> #include<cstring> #include<algorithm> #define gc getchar() #define pc putchar inline int read() { int x = 0,f = 1; char c = gc; while(c < '0' || c > '9') {if(c == '-')f = -1; char c = getchar();} while(c <= '9' && c >= '0') x = x * 10 + c - '0',c = getchar(); return x * f; } void print(int x) { if(x < 0) { pc('-'); x = -x; } if(x >= 10) print(x / 10); pc(x % 10 + '0'); } const int maxn = 100007; int a[maxn]; int main() { int n = read(),k = read(); for(int i = 1;i <= n;++ i) a[i] = read(); std::sort(a + 1, a + n + 1); int ans = 0; for(int i = 1;i <= n;++ i) { if(i < n) { if(a[i] <= k ) k -= a[i],ans ++;} else if(i == n && a[i] == k) ans ++; else break; } print(ans); pc('\n'); }
AGC027 A - Candy Distribution Again