LeetCode-402. Remove K Digits
阿新 • • 發佈:2018-11-02
https://leetcode.com/problems/remove-k-digits/description/
Given a non-negative integer num represented as a string, remove k digits from the number so that the new number is the smallest possible.
Note:
- The length of num is less than 10002 and will be ≥ k.
- The given num
Example 1:
Input: num = "1432219", k = 3
Output: "1219"
Explanation: Remove the three digits 4, 3, and 2 to form the new number 1219 which is the smallest.
Example 2:
Input: num = "10200", k = 1 Output: "200" Explanation: Remove the leading 1 and the number is 200. Note that the output must not contain leading zeroes.
Example 3:
Input: num = "10", k = 2
Output: "0"
Explanation: Remove all the digits from the number and it is left with nothing which is 0.
題解:想了很久吧這題,之前用vector但是超時,後來發現string類也有push_back,back,pop_back之類的函式= =
class Solution { public: string removeKdigits(string num, int k){ int l = num.length(); int n = l - k; string v; v.clear(); if (k >= l || l == 0){ return "0"; } else if (k <= 0){ return num; } for (int i = 0; i < l; i++){ while (k > 0 && num[i] < v.back() && v.size() > 0){ v.pop_back(); k--; } v.push_back(num[i]); } string ans = ""; for (int i = 0; i < n; i++){ ans += v[i]; } while (ans[0] == '0'){ ans.erase(0, 1); } if (ans.length() != 0){ return ans; } else { return "0"; } } };