11. Container With Most Water C++
方法1:Brute Force(執行時間慘不忍睹,共進行)
class Solution { public: int maxArea(vector<int>& height) { int res=0; for(int i=0;i<height.size();i++) for(int j=i+1;j<height.size();j++) res = max(res,min(height[i],height[j])*(j-i)); return res; } };
11. Container With Most Water C++
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info col pub 技術 bubuko size area bsp alt 方法1:Brute Force(執行時間慘不忍睹,共進行) class Solution { public: int maxArea(vector<int>& h
【LeetCode】11. Container With Most Water(盛最多水的容器)-C++實現的三種方法
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[leecode]---11.container with most water
description: Input: [1,8,6,2,5,4,8,3,7]Output: 49 思路1: 從(1,a1)開始向後算面積,需要兩層n迴圈,時間複雜度n2 思路2: 找出陣列中最大的數,將其與次
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