經典的應用

public class TestTransaction {
	
	List<Transaction> transactions = null;
	
	@Before
	public void before(){
		Trader raoul = new Trader("Raoul", "Cambridge");
		Trader mario = new Trader("Mario", "Milan");
		Trader alan = new Trader("Alan", "Cambridge");
		Trader brian = new
 
 Trader("Brian", "Cambridge");
		
		transactions = Arrays.asList(
				new Transaction(brian, 2011, 300),
				new Transaction(raoul, 2012, 1000),
				new Transaction(raoul, 2011, 400),
				new Transaction(mario, 2012, 710),
				new Transaction(mario, 2012, 700),
				new Transaction(alan, 2012, 950)
		);
	}
	
	//1. 找出2011年發生的所有交易， 並按交易額排序（從低到高）
 

	@Test
	public void test1(){
		transactions.stream()
					.filter((t) -> t.getYear() == 2011)
					.sorted((t1, t2) -> Integer.compare(t1.getValue(), t2.getValue()))
					.forEach(System.out::println);
	}
	
	//2. 交易員都在哪些不同的城市工作過？
	@Test
	public void test2(){
		transactions.stream()
					.map((t)
 
 -> t.getTrader().getCity())
					.distinct()
					.forEach(System.out::println);
	}
	
	//3. 查詢所有來自劍橋的交易員，並按姓名排序
	@Test
	public void test3(){
		transactions.stream()
					.filter((t) -> t.getTrader().getCity().equals("Cambridge"))
					.map(Transaction::getTrader)
					.sorted((t1, t2) -> t1.getName().compareTo(t2.getName()))
					.distinct()
					.forEach(System.out::println);
	}
	
	//4. 返回所有交易員的姓名字串，按字母順序排序
	@Test
	public void test4(){
		transactions.stream()
					.map((t) -> t.getTrader().getName())
					.sorted()
					.forEach(System.out::println);
		
		System.out.println("-----------------------------------");
		
		String str = transactions.stream()
					.map((t) -> t.getTrader().getName())
					.sorted()
					.reduce("", String::concat);
		
		System.out.println(str);
		
		System.out.println("------------------------------------");
		
		transactions.stream()
					.map((t) -> t.getTrader().getName())
					.flatMap(TestTransaction::filterCharacter)
					.sorted((s1, s2) -> s1.compareToIgnoreCase(s2))
					.forEach(System.out::print);
	}
	
	public static Stream<String> filterCharacter(String str){
		List<String> list = new ArrayList<>();
		
		for (Character ch : str.toCharArray()) {
			list.add(ch.toString());
		}
		
		return list.stream();
	}
	
	//5. 有沒有交易員是在米蘭工作的？
	@Test
	public void test5(){
		boolean bl = transactions.stream()
					.anyMatch((t) -> t.getTrader().getCity().equals("Milan"));
		
		System.out.println(bl);
	}
	
	
	//6. 列印生活在劍橋的交易員的所有交易額
	@Test
	public void test6(){
		Optional<Integer> sum = transactions.stream()
					.filter((e) -> e.getTrader().getCity().equals("Cambridge"))
					.map(Transaction::getValue)
					.reduce(Integer::sum);
		
		System.out.println(sum.get());
	}
	
	
	//7. 所有交易中，最高的交易額是多少
	@Test
	public void test7(){
		Optional<Integer> max = transactions.stream()
					.map((t) -> t.getValue())
					.max(Integer::compare);
		
		System.out.println(max.get());
	}
	
	//8. 找到交易額最小的交易
	@Test
	public void test8(){
		Optional<Transaction> op = transactions.stream()
					.min((t1, t2) -> Integer.compare(t1.getValue(), t2.getValue()));
		
		System.out.println(op.get());
	}

}

public class TestStreamAPI {
	
	/*
	  	1.	給定一個數字列表，如何返回一個由每個數的平方構成的列表呢？
		，給定【1，2，3，4，5】， 應該返回【1，4，9，16，25】。
	 */
	@Test
	public void test1(){
		Integer[] nums = new Integer[]{1,2,3,4,5};
		
		Arrays.stream(nums)
			  .map((x) -> x * x)
			  .forEach(System.out::println);
	}

	/*
	 2.	怎樣用 map 和 reduce 方法數一數流中有多少個Employee呢？
	 */
	List<Employee> emps = Arrays.asList(
			new Employee(102, "李四", 59, 6666.66, Status.BUSY),
			new Employee(101, "張三", 18, 9999.99, Status.FREE),
			new Employee(103, "王五", 28, 3333.33, Status.VOCATION),
			new Employee(104, "趙六", 8, 7777.77, Status.BUSY),
			new Employee(104, "趙六", 8, 7777.77, Status.FREE),
			new Employee(104, "趙六", 8, 7777.77, Status.FREE),
			new Employee(105, "田七", 38, 5555.55, Status.BUSY)
	);
	
	@Test
	public void test2(){
		Optional<Integer> count = emps.stream()
			.map((e) -> 1)
			.reduce(Integer::sum);
		
		System.out.println(count.get());
	}
}