python如果需要將物件存成檔案，方便以後（或放在其他地方）使用，可以使用序列化pickle，

參考另一篇隨筆：https://www.cnblogs.com/taoshiqian/p/9771786.html

但是一個較大的物件簡單序列化成檔案，可能會佔用很大空間，而此時物件中可能有很多重複資訊，完全可以壓縮儲存

因此，物件->檔案：序列化+壓縮，檔案->物件：解壓+反序列化，更省空間

import os, pickle, gzip


def save_object_to_zip(objects, filename):
    if not os.path.exists(filename):
        
 
if os.path.split(filename)[0]:  # 需要資料夾
            os.mkdir(os.path.split(filename)[0])  # 建立資料夾
        os.mknod(filename)  # 建立檔案
    fil = gzip.open(filename, 'wb')
    pickle.dump(objects, fil)
    fil.close()


def load_object_from_zip(filename):
    fil = gzip.open(filename, 'rb')
    while True:
        
 
try:
            return pickle.load(fil)
        except EOFError:
            break
    fil.close()


def test_pickle_and_zip():
    L1 = [1, 2, 3, 4, 5]
    filename = 'L'
    save_object_to_zip(L1, filename)
    L2 = load_object_from_zip(filename)
    print(L2)
    print(type(L2))

    L1 = 8
    filename 
 
= 'int/L'
    save_object_to_zip(L1, filename)
    L2 = load_object_from_zip(filename)
    print(L2)
    print(type(L2))

    L1 = {'a': 1, 'b': 2}
    filename = 'int/L'
    save_object_to_zip(L1, filename)
    L2 = load_object_from_zip(filename)
    print(L2)
    print(type(L2))


if __name__ == '__main__':
    test_pickle_and_zip()

#輸出

[1, 2, 3, 4, 5]
<class 'list'>

8
<class 'int'>

{'a': 1, 'b': 2}
<class 'dict'>