657. Robot Return to Origin
x,y兩個變數,這道問題解決 執行效率很高,以後不用多看這題,賊簡單的那種
bool judgeCircle(string moves) { int i = 0; int x = 0, y = 0; while(moves[i] != '\0'){ char c = moves[i]; switch (c){ case 'U': y++; break; case 'D': y--; break; case 'R': x++; break; case 'L': x--; break; } i++; } if(x == 0 && y == 0) return true; else return false; }
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