Leetcode 657. Robot Return to Origin
class Solution: def judgeCircle(self, moves: str) -> bool: location = [0, 0] for m in moves: if m == ‘L‘: location[0] -= 1 elif m == ‘R‘: location[0] += 1 elif m == ‘U‘: location[1] += 1else: location[1] -= 1 return location[0] == 0 and location[1] == 0
Leetcode 657. Robot Return to Origin
相關推薦
leetcode 657. Robot Return to Origin(水)
There is a robot starting at position (0, 0), the origin, on a 2D plane. Given a sequence of its moves, judge if this robot ends up
LeetCode 657.Robot Return to Origin( 機器人能否返回原點) C++ JAVA實現
There is a robot starting at position (0, 0), the origin, on a 2D plane. Given a sequence of its moves, judge if this robot ends up at (0,
leetcode 657. Robot Return to Origin (Python)
657. Robot Return to Origin There is a robot starting at position (0, 0), the origin, on a 2D plane. Given a sequence of its moves, judge
LeetCode 657 Robot Return to Origin 解題報告
題目要求 There is a robot starting at position (0, 0), the origin, on a 2D plane. Given a sequence of its moves, judge if this robot ends up at (0, 0)&nb
Leetcode 657. Robot Return to Origin
bool turn += class leetcode urn etc lse location class Solution: def judgeCircle(self, moves: str) -> bool: location =
【LeetCode】657. Robot Return to Origin 解題報告(Python)
作者: 負雪明燭 id: fuxuemingzhu 個人部落格: http://fuxuemingzhu.cn/ 目錄 題目描述 題目大意 解題方法 複數求和 counter統計次數
【leetcode】657. Robot Return to Origin
因此 註意 note 相同 ++ ant return art posit Algorithm 【leetcode】657. Robot Return to Origin https://leetcode.com/problems/robot-return-to-origi
657. Robot Return to Origin
x,y兩個變數,這道問題解決 執行效率很高,以後不用多看這題,賊簡單的那種 bool judgeCircle(string moves) { int i = 0; int x = 0, y = 0; while(moves[i] != '
leetcode (Robot Return to Origin)
Title:Robot Return to Origin 657 Difficulty:Easy 原題leetcode地址:https://leetcode.com/problems/robot-return-to-origin/ 1.&n
C#LeetCode刷題之#657-機器人能否返回原點(Robot Return to Origin)
問題 在二維平面上,有一個機器人從原點 (0, 0) 開始。給出它的移動順序,判斷這個機器人在完成移動後是否在 (0, 0) 處結束。 移動順序由字串表示。字元 move[i] 表示其第 i 次移動。機器人的有效動作有 R(右),L(左),U(上)和 D(下)。如果機器人在完成所有動作後
leetcode 657. 機器人能否返回原點(Robot Return to Origin)
沒有 結束 str 假設 解法 人的 ring false 開始 目錄 題目描述: 示例 1: 示例 2: 解法: 題目描述: 在二維平面上,
10. Robot Return to Origin
and seq sta aci ive HERE character ria end Title: There is a robot starting at position (0, 0), the origin, on a 2D plane. Given a seque
Leetcode 973. K Closest Points to Origin
We have a list of points on the plane. Find the K closest points to the origin (0, 0). (Here, the distance bet
119th LeetCode Weekly Contest K Closest Points to Origin
We have a list of points on the plane. Find the K closest points to the origin (0, 0). (Here, the distance between two poin
[LeetCode] Flatten Binary Tree to Linked List
mil neu pan gin 一次 ng- mon example style Given a binary tree, flatten it to a linked list in-place. For example, Given 1
[LeetCode] 121. Best Time to Buy and Sell Stock Java
most length 如果 時間復雜度 ase 最大差值 new [1] cas 題目: Say you have an array for which the ith element is the price of a given stock on day i.
[Leetcode] Convert sorted list to binary search tree 將排好的鏈表轉成二叉搜索樹
sea lan 返回 使用 但是 right end 題目 blog ---恢復內容開始--- Given a singly linked list where elements are sorted in ascending order, convert it to a
[LeetCode] 22. Best Time to Buy and Sell Stock II Java
股票 log ive highlight transacti ever 方法 size 可能 題目: Say you have an array for which the ith element is the price of a given stock on day i
[Leetcode] convert sorted array to binary search tree
get left bsp sea class 方法 return for target Given an array where elements are sorted in ascending order, convert it to a height balanced
leetcode 121. Best Time to Buy and Sell Stock
clas which style ces pre max des sign har Say you have an array for which the ith element is the price of a given stock on day i. If you